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enot [183]
4 years ago
8

Consider three scenarios in which a particular box moves downward under the pull of gravity :

Physics
1 answer:
luda_lava [24]4 years ago
5 0

Answer:

1. True  WA > WB > WC

Explanation:

In this exercise they give work for several different configurations and ask that we show the relationship between them, the best way to do this is to calculate each work separately.

A) Work is the product of force by distance and the cosine of the angle between them

    WA = W h cos 0

   WA = mg h

B) On a ramp without rubbing

     Sin30 = h / L

     L = h / sin 30

     WB = F d cos θ  

     WB = F L cos 30

     WB = mf (h / sin30) cos 30

     WB = mg h ctan 30

C) Ramp with rubbing

    W sin 30 - fr = ma

   N- Wcos30 = 0

   W sin 30 - μ W cos 30 = ma

    F = W (sin30 - μ cos30)

   WC = mg (sin30 - μ cos30) h / sin30

   Wc = mg (1 - μ ctan30) h

When we review the affirmation it is the work where there is rubbing is the smallest and the work where it comes in free fall at the maximum

Let's review the claims

1. True The work of gravity is the greatest and the work where there is friction is the least

2 False. The job where there is friction is the least

3 False work with rubbing is the least

4 False work with rubbing is the least

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A 2800 kg truck moving at 12 m/s to the right hits a stopped 1100 kg car. What is the combined velocity the moment they stick to
leva [86]

Answer:

The combined velocity is 8.61 m/s.

Explanation:

Given that,

The mass of a truck, m = 2800 kg

Initial speed of truck, u = 12 m/s

The mass of a car, m' = 1100 kg

Initial speed of the car, u' = 0

We need to find the combined velocity the moment they stick together. Let it is V. Using the conservation of momentum.

m_1v_1+m_2v_2=(m_1+m_2)V\\\\V=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}\\\\V=\dfrac{2800\times 12+0}{2800+1100}\\\\V=8.61\ m/s

So, the combined velocity is 8.61 m/s.

5 0
3 years ago
A body moves in a straight line. At time, it's acceleration is given by a = 12t + 1. When t =0, the velocity of the body v is 2
madreJ [45]

Answer:

v = 6t² + t + 2, s = 2t³ + ½ t² + 2t

59 m/s, 64.5 m

Explanation:

a = 12t + 1

v = ∫ a dt

v = 6t² + t + C

At t = 0, v = 2.

2 = 6(0)² + (0) + C

2 = C

Therefore, v = 6t² + t + 2.

s = ∫ v dt

s = 2t³ + ½ t² + 2t + C

At t = 0, s = 0.

0 = 2(0)³ + ½ (0)² + 2(0) + C

0 = C

Therefore, s = 2t³ + ½ t² + 2t.

At t = 3:

v = 6(3)² + (3) + 2 = 59

s = 2(3)³ + ½ (3)² + 2(3) = 64.5

5 0
3 years ago
Density of solids What is your hypothesis (or hypotheses) for this experiment?.
valentina_108 [34]

I formulate a hypothesis based on their observations about what occurs when both the rock and the wood are submerged in water.

<h3 /><h3>What is density?</h3>

Density is defined as the mass per unit volume. It is an important parameter in order to understand the fluid and its properties. Its unit is kg/m³.

The mass and density relation is given as

mass = density × volume

I study if the volume or density of items determines whether solid objects float or sink in water in this scientific inquiry I did the experiment of density, mass, and volume using a rock and a standard-shaped piece of wood.

It is critical that the chosen piece of wood is larger than the rock and that the rock be tiny enough to fit inside the measuring cylinder. I see both the rock and a chunk of wood.

Hence I formulate a hypothesis based on their observations about what occurs when both the rock and the wood are submerged in water.

To learn more about the density refers to the link;

brainly.com/question/952755

7 0
3 years ago
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IceJOKER [234]
Hello.

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</span>
Have a nice day
3 0
3 years ago
A flywheel having constant angular acceleration requires 4.00 ss to rotate through 164 radrad . Its angular velocity at the end
ExtremeBDS [4]

Answer:

\omega '=-13.5rad/s

Explanation:

From the question we are told that:

Time t=4sec

Angular displacement \theta= 161 rad

Final Angular velocity  \omega = 100 rad / s

Let

Angular acceleration \alpha  

Generally the equation for Initial Angular velocity  \omega ' is mathematically given by

-\omega '^2=2 \alpha \theta -\omega^2

\omega '^2= \alpha 328 +11236

Also,Initial Angular velocity  \omega ' is mathematically given by

\omega '=\omega  - \alpha t

Therefore substitution

-\omega '^2=2 \alpha \theta -\omega^2

\omega '=\omega  - \alpha t

(\omega  - \alpha t)^2=2 \alpha \theta -\omega

-16\alpha^2+848\alpha+11236= \alpha 328 -11236

16\alpha^2-520\alpha=0

\alpha=29.875rads/s^2

Substitution in the 2nd equation for Initial Angular velocity  \omega '

\omega '=106-(29.875rads/s^2*4)

\omega '=-13.5rad/s

6 0
3 years ago
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