The wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is 1.978 meter
According to the question
The frequency of a photon of electromagnetic radiation = 151.7 Mhz
By using the Formula of wavelength and frequency
λ = C/f
Where,
λ (Lambda) = Wavelength in meters
C = Speed of Light (c = 3x10⁸ m/s)
f = Frequency
Now, the wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is
1 Mhz = 1000000 Hz
151.7 Mhz = 151.7 * 10⁶ Hz
λ = C/f
Substituting the value of C and f
λ =
λ = 1.978 meter
Hence, the wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is 1.978 meter
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Answer:
a) The velocity of the car is 7.02 m/s and the car is approaching to the police car as the frequency of the police car is increasing.
b) The frequency is 1404.08 Hz
Explanation:
If the police car is a stationary source, the frequency is:
(eq. 1)
fs = frequency of police car = 1200 Hz
fa = frequency of moving car as listener
v = speed of sound of air
vc = speed of moving car
If the police car is a stationary observer, the frequency is:
(eq. 2)
Now,
fL = frequecy police car receives
fs = frequency police car as observer
a) The velocity of car is from eq. 2:

b) Substitute eq. 1 in eq. 2:

Answer : The correct option is, (d) 4 times
Solution :
According to the Coulomb's law, the electrostatic force of attraction or repulsion between two charges is directly proportional to the product of the charges and is inversely proportional to the square of the distance between the the charges.
Formula used :

where,
F = electrostatic force of attraction or repulsion
= Coulomb's constant
and
are the charges
r = distance between two charges
First we have to calculate the force exerted between S and q when the distance between the charge is 1 unit and let us assumed that the charge be 'q'
..........(1)
Now we have to calculate the force exerted between S and p when the distance between the charge is 2 unit at the same charge.
...........(2)
Equation equation 1 and 2, we get


Therefore, the force exerted between S and q is 4 times the force exerted between S and p.
A. Minerals would dissolve faster at the bottom of a waterfall than at a still pond because the water is more turbulent at the base of the waterfall. The turbulent water has more energy and would facilitate faster dissolution of minerals.
B. Minerals would dissolve faster in warmer water downstream because the warm water would speed up the rate of dissolution.
C. Minerals in the sand would dissolve faster because the sand is in small grains and so more surface area is available for dissolution.
Answer:
The max speed is 8m/s, 3 seconds at this speed gives 24mts, at 9 seconds has traveled 64mts and at 7,5 52mts
Explanation:
The max speed can be calculated since, at 6 seconds is at 40 mts from the starting point and at constant speed is at 72 mts 10 seconds after the start of the race, then the constant max speed is (72-40)mts /(10-6)seconds=8 m/s.
the distanced travel at this speed is obtained by multipliying by 3 seconds. that is 8m/s*3s=24 mts. the distance at 9 seconds is 40mt of initial 6 plus 24 additional, that is 64mts and at 7,5 is the 40mts initial plus the 13 additional from 8m/s*1,5s = 12mt, that is 52mts.