The answer would be A and I’m pretty sure of thta
To have a force of 3.8x10-8 the two chaarges must be 0.65m apart.
We have that for the Question, it can be said that the amount by which the length of the stack decreases is
From the question we are told
A copper (<em>Young's modulus </em>1.1 x 1011 N/m2) cylinder and a brass (Young's modulus 9.0 x 1010 N/m2) cylinder are stacked end to end, as in the drawing. Each <em>cylinder </em>has a radius of 0.24 cm.
A compressive force of F = 7900 N is applied to the right end of the brass cylinder. Find the amount by which the length of the stack <em>decreases</em>.
Generally the equation for <em>copper </em>cylinder is mathematically given as



Generally the equation for brass<em> </em>cylinder is mathematically given as


Therefore Total change in length


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Answer:
Δλ = 3*10⁻³ m.
Explanation:
- At any wave, there exists a fixed relationship between the speed of the wave, the wavelength, and the frequency, as follows:

where v is the speed, λ is the wavelength and f is the frequency.
- Rearranging terms, we can get λ from the other two parameters, as follows:

- Since v is constant for sound at 343 m/s, we can find the different wavelengths at different frequencies, as follows:


- The difference between both wavelengths, is just the difference between (3) and (4):

⇒ Δλ = 3*10⁻³ m.
If 1 second = 10000 μs
what about how many seconds = 0.77 μs
the calculations would be done lke this
0.77 x 1/1000000 = 7.7 x 10 ^ -7
Speed = distance / time
distance = length of the spacecraft
therefore speed = 250/7.7 x 10^ -7
ans = 324675324.7 m/s