All categories

2 years ago

Diamonds are a very dense material. Predict what would happen to the light ray if you projected it from air through a diamond

Physics

2 answers:

Anni [7]2 years ago

5 0

Answer:

a cat could eat it

Explanation:

Fluffy ate my diamond

Kipish [7]2 years ago

4 0

Answer:

It [the diamond] would act like a prism, and make a rainbow, or, the light would break up and disappear

Explanation:

that's what I would think at least

You might be interested in

Calculate the wavelength of a photon of electromagnetic radiation with a frequency of 151.7 mhz

AlekseyPX

The wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is 1.978 meter

According to the question

The frequency of a photon of electromagnetic radiation = 151.7 Mhz

By using the Formula of wavelength and frequency

λ = C/f

Where,

λ (Lambda) = Wavelength in meters

C = Speed of Light (c = 3x10⁸ m/s)

f = Frequency

Now, the wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is

1 Mhz = 1000000 Hz

151.7 Mhz = 151.7 * 10⁶ Hz

λ = C/f

Substituting the value of C and f

λ = $\frac{3*10^{8} }{151.7 * 10^{6} }$

λ = 1.978 meter

Hence, the wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is 1.978 meter

To know more about wavelength and frequency here:

brainly.com/question/18651058

#SPJ4

5 0

2 years ago

Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. A stationary police car emits a sound of frequen

bixtya [17]

Answer:

a) The velocity of the car is 7.02 m/s and the car is approaching to the police car as the frequency of the police car is increasing.

b) The frequency is 1404.08 Hz

Explanation:

If the police car is a stationary source, the frequency is:

$f_{a} =(\frac{v+v_{c} }{v} )f_{s}$ (eq. 1)

fs = frequency of police car = 1200 Hz

fa = frequency of moving car as listener

v = speed of sound of air

vc = speed of moving car

If the police car is a stationary observer, the frequency is:

$f_{L} =f_{a} (\frac{v}{v-v_{c} } )=(\frac{v+v_{c} }{v-v_{c} } )f_{s}$ (eq. 2)

Now,

fL = frequecy police car receives

fs = frequency police car as observer

a) The velocity of car is from eq. 2:

$1250=1200(\frac{v+v_{c} }{v-v_{c} } )\\1250(v-v_{c} )=1200(v+v_{c} )\\v_{c} =\frac{50*344}{2450} =7.02m/s$

b) Substitute eq. 1 in eq. 2:

$f_{L} =(\frac{v+v_{p} }{v-v_{c} } )(\frac{v+v_{c} }{v-v_{p} } )f_{s} =(\frac{344+20}{344-7.02} )(\frac{344+7.02}{344-20} )*1200=1404.08Hz$

7 0

4 years ago

Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S an

insens350 [35]

Answer : The correct option is, (d) 4 times

Solution :

According to the Coulomb's law, the electrostatic force of attraction or repulsion between two charges is directly proportional to the product of the charges and is inversely proportional to the square of the distance between the the charges.

Formula used :

$F=k_e\frac{q_1q_2}{r^2}$

where,

F = electrostatic force of attraction or repulsion

$k_e$ = Coulomb's constant

$q_1$ and $q_2$ are the charges

r = distance between two charges

First we have to calculate the force exerted between S and q when the distance between the charge is 1 unit and let us assumed that the charge be 'q'

$F_{sq}=k_e\frac{qq}{1^2}=k_e\times q^2$ ..........(1)

Now we have to calculate the force exerted between S and p when the distance between the charge is 2 unit at the same charge.

$F_{sp}=k_e\frac{qq}{2^2}=k_e\frac{q^2}{4}$ ...........(2)

Equation equation 1 and 2, we get

$\frac{F_{sq}}{F_{sp}}=\frac{1}{4}$

$F_{sq}=4\times F_{sp}$

Therefore, the force exerted between S and q is 4 times the force exerted between S and p.

5 0

3 years ago

Read 2 more answers

Some of the minerals found in rocks dissolve in water as it flows over the rocks. would these minerals dissolve more quickly

densk [106]

A. Minerals would dissolve faster at the bottom of a waterfall than at a still pond because the water is more turbulent at the base of the waterfall. The turbulent water has more energy and would facilitate faster dissolution of minerals.

B. Minerals would dissolve faster in warmer water downstream because the warm water would speed up the rate of dissolution.

C. Minerals in the sand would dissolve faster because the sand is in small grains and so more surface area is available for dissolution.

7 0

3 years ago

When running a 100 meter race Trevor reaches his maximum speed when he is 40 meters from the starting line, and 6 seconds have e

Virty [35]

Answer:

The max speed is 8m/s, 3 seconds at this speed gives 24mts, at 9 seconds has traveled 64mts and at 7,5 52mts

Explanation:

The max speed can be calculated since, at 6 seconds is at 40 mts from the starting point and at constant speed is at 72 mts 10 seconds after the start of the race, then the constant max speed is (72-40)mts /(10-6)seconds=8 m/s.

the distanced travel at this speed is obtained by multipliying by 3 seconds. that is 8m/s*3s=24 mts. the distance at 9 seconds is 40mt of initial 6 plus 24 additional, that is 64mts and at 7,5 is the 40mts initial plus the 13 additional from 8m/s*1,5s = 12mt, that is 52mts.

6 0

4 years ago

Read 2 more answers