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3 years ago

3(5-9b)+11=-244 solve for b

Mathematics

2 answers:

ryzh [129]3 years ago

6 0

B= -218/27 when solving for b

natta225 [31]3 years ago

3 0

15-27b+11=-244
26-27b=-244
-27b=-270
b=10

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Anyone know this and can help?!

DENIUS [597]

Answer:

65.4°

Step-by-step explanation:

According to question

The equation is

Cos(x)=5/12

x=acos(5/12)

x=65.4°

7 0

2 years ago

Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be

hodyreva [135]

Answer:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

And the sample deviation with the following formula:

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

And the sample deviation with the following formula:

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

8 0

3 years ago

A fruit company sells two types of boxes large and small. A delivery of two large boxes and three small boxes has a total weight

lara31 [8.8K]

Answer:

the large box weight is 6.50 kg and the small box weight is 13.75 kg

Step-by-step explanation:

The computation of each type of box weight is as follows:

Let us assume the large box be x

And, the small box be y

So,

2x + 3y = 47.......(i)

6x + 5y = 115........(ii)

Multiply by 3 in equation 1

6x + 9y = 141

6x + 5y = 115

Now subtract the last equation from the above one

4y = 26

y = 6.50

For x, it would be

2x+ 3(6.50) = 47

2x + 19.5 = 47

2x = 47 - 19.50

2x = 27.50

x = 13.75

Hence, the large box weight is 6.50 kg and the small box weight is 13.75 kg

4 0

2 years ago

Helen earns $12 each weekend by babysitting her brother.After the third weekend,Helen buys a new cd for $12.48.How much money do

GalinKa [24]

She would have $23.52 because 12 times 3 is 36 and 36-12.48=23.52

6 0

3 years ago

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What is the reciprocal of -2 2/3

BaLLatris [955]

Answer:

-3/8

Step-by-step explanation:

First rewrite -2 2/3 as an improper fraction: -8/3

Now invert this result: -3/8

This is the reciprocal of -2 2/3.

3 0

2 years ago

Read 2 more answers