Answer:
→ The table is:
→ x → -1 → 0 → 1
→ y → -3 → 0 → 3
The graph of the line is figure d
Step-by-step explanation:
∵ y = 3x
∵ x = -1, 0, 1
→ Substitute the values of x in the equation to find the values of y
∴ y = 3(-1) = -3
∴ y = 3(0) = 0
∴ y = 3(1) = 3
→ The table is:
→ x → -1 → 0 → 1
→ y → -3 → 0 → 3
∵ The form of the linear equation is y = m x + b, where
∵ y = 3x
→ Compare the equation with the form
∴ m = 3
∴ b = 0
→ That means the slope is positive, then the direction of the line must
be from left tp right and passes through the origin
∴ The graph of the line is figure d
Average acceleration = (173-0)/39=4.44m/s^2
Radius, r = 3
The equation of a sphere entered at the origin in cartesian coordinates is
x^2 + y^2 + z^2 = r^2
That in spherical coordinates is:
x = rcos(theta)*sin(phi)
y= r sin(theta)*sin(phi)
z = rcos(phi)
where you can make u = r cos(phi) to obtain the parametrical equations
x = √[r^2 - u^2] cos(theta)
y = √[r^2 - u^2] sin (theta)
z = u
where theta goes from 0 to 2π and u goes from -r to r.
In our case r = 3, so the parametrical equations are:
Answer:
x = √[9 - u^2] cos(theta)
y = √[9 - u^2] sin (theta)
z = u
Answer:
x^2 y^2(x+y)(x^2 - xy + y^2)
Step-by-step explanation:
x^2 y^2(x^3 + y^3)
(x+y)(x^2 - xy +y^2)
