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Nataly_w [17]
3 years ago
11

Which phrase is evidence of the limits of what science can study?

Physics
1 answer:
Furkat [3]3 years ago
5 0

Answer:GIVE ME ANSWERRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR

Explanation: ujhbuewgruh guygdsfytdfty sabjkxnfcjizhuihbtdastged7asgbn&Tgsagyaugdy7sgb67qYGSHFHUDUB8D T IFGJHIGFJHIGJF HELP ME I NEED THE ANSWER

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Rank in order the following according to their speeds, from fastest to slowest: (i) 425-nm-wavelength light through a pane of gl
kotegsom [21]

Answer:

v > ii > iii > i > iv

Explanation:

The speed of light does not depend on the wavelength of light rather the medium through which it passes through.

v) The speed of light in a vacuum is maximum = 300000 km/s

ii) The speed of light in air = 2999910.026 km/s

iii) The speed of light in water = 2255639.097 km/s

i) The speed of light in glass = 1973684.210 km/s

iv) The speed of light in diamonds = 1239669.421 km/s

Hence the ranking will be

v > ii > iii > i > iv

5 0
3 years ago
One component of a metal sculpture consists of a solid cube with an edge of length 24.5 cm . The alloy used to make the cube has
boyakko [2]

Answer:

118kg

Explanation:

answered

Given

density of the cube= 8050 kg/m3 .

length of the sizes of the cube=24.5 cm

We can convert the length to cm for unit consistency.

It's length =24.5 cm =0.245m

✓ the length of sizes of the cube is the same, then the volume can be calculated as

Volume= L^3

= (0.245m)^3

=0.01470625 m^3

✓ but we know that

Density = mass/ volume

Then,

Mass= (Volume × density)

= (0.01470625)(8050)

= 118 kg

Hence, the mass of the cube is 118 kg

8 0
3 years ago
Two balls move away from each other, both traveling at 7 m/s. One has a mass of 2 kg and the other has a mass of 3 kg
zavuch27 [327]
A 300-kg bear grasping a vertical tree slides down at constant velocity. The friction force between the
tree and the bear is
5 0
3 years ago
Consider the path of a comet orbiting a star, the system of the comet plus the star. Which of the following statements are corre
Stels [109]

Answer:

True  1, 4

False 2, 3, 5

Explanation:

The system is formed by the Sun that is fixed at a point (focus of movement) and the comet that rotates around in styptic orbits. The only force involved is the force of attraction between the two bodies, if we write the energy of the system

         Em = K + U

         Em = ½ m v2 + G m Ms / r2

where m is the mass of the comet, Ms the mass of the Sun and r the distance between them.

This system is isolated so the energy is conserved throughout the movement, it only transforms from kinetic to gravitational potential.

Let's review the different claims;

1) True. The speed of the comet determines its kinetic energy, so when decreasing the speed decreases the kinetic energy, there is also a decrease due to the lost mass

2) False. The total energy is constant, so if the kinetic energy increases, the power energy must decrease

3) False. The comet's speed changes are due to changes in gravitational energy, so no external work is needed to change the speed.

4) True. Correct because the sum of the two must be constant

5) False. When the comet loses speed, the energy increases, the power would gravitate, so there is no loss of energy, we are ignoring the loss of mass of the comet.

8 0
3 years ago
A 6.0-kg object moving at 5.0 m/s collides with and sticks to a 2.0-kg object. After the collision the composite object is movin
gogolik [260]

Answer:

a) 23 m/s

Explanation:

  • Assuming no external forces acting during the collision, total momentum must be conserved, as follows:

       p_{o} = p_{f}  (1)

  • The initial momentum p₀, can be written as follows:

       p_{o} =  m_{1}  * v_{1o} + m_{2}* v_{2o} =   6.0 kg * 5.0 m/s + 2.0 kg * v_{2o}  (2)

  • The final momentum pf, can be written as follows:

        p_{f} = (m_{1} + m_{2} )* v_{f}  = 8.0 kg* (-2.0 m/s)  (3)

  • Since (2) and (3) are equal each other, we can solve for the only unknown that remains, v₂₀, as follows:

       v_{2o} = \frac{-6.0kg* 5m/s -8.0 kg*2.0m/s}{2.0kg}  = \frac{-46kg*m/s}{2.0kg} = -23.0 m/s  (4)

  • This means that the 2.0-kg object was moving at 23 m/s in a direction opposite to the 6.0-kg object, so its initial speed, before the collision, was 23.0 m/s.
6 0
3 years ago
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