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cluponka [151]
3 years ago
11

A solid block of mass m is suspended in a liquid by a thread. The density of the block is greater than that of the liquid. Initi

ally, the fluid level is such that the block is at a depth d and the tension in the thread is T. Then, the fluid level is decreased such that the depth is 0.5d. What is the tension in the thread when the block is at the new depth?

Physics
1 answer:
Tanzania [10]3 years ago
3 0

Answer:

(C) T

The tension T at equilibrium will be equal to the Buoyant force.

The Buoyant force is given by:

Fb = density x acceleration due to gravity x volume displaced

The change in height doesn't affect the Buoyant force and hence the tension.

Note: The figure of question is added in the attachment

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frutty [35]

Energy of wave depends on its amplitude and it is given as

E = \frac{1}{2} kA^2

here k = constant

A = amplitude

so energy will increase or decrease depends on the amplitude of the wave

So here if we need to check which wave has lower energy then we need to compare the amplitude.

If the amplitude is less then energy must be less

So please check in the figure that which wave out of A and B has lesser amplitude to find out the wave of lesser energy

5 0
3 years ago
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Spaceship 1 and spaceship 2 have equal masses of 200 kg. Spaceship 1 has a speed of 0 m/s, and spaceship 2 has a speed of 10 m/s
m_a_m_a [10]

Answer:

2000 kg m/s

Explanation:

The momentum of an object is a vector quantity whose magnitude is given by

p=mv

where

m is the mass of the object

v is the velocity of the object

and its direction is the same as the velocity.

In this problem, we have:

- Spaceship 1 has

m = 200 kg (mass)

v = 0 m/s (zero velocity)

So its momentum is

p_1 =(200)(0)=0

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v = 10 m/s (velocity)

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3 0
3 years ago
A nichrome wire has a resistance of 5
kari74 [83]

Answer:

R = 6.67 Ohm's

Explanation:

Resistance is a property of a material that measures the opposition to the flow of current through the material. It is measured in Ohm's.

              R = (ρl) ÷ A

where; R is the resistance of the material, A is its cross sectional area, l is its length and ρ is its resistivity.

For the first nichrome wire, resistance is 5 Ohm's.

i.e            R = (ρl) ÷ A = 5 Ohm's

For the second nichrome wire, length = 4l, and area of cross section = 3A. The resistance of the second wire can be determined by;

R = (4ρl) ÷ 3A

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   =  \frac{4}{3} × 5

R = 6.67 Ohm's

Resistance of the second nichrome wire is  6.67 Ohm's.

4 0
3 years ago
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30.0m in 2.00 s thats the answer
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