Energy of wave depends on its amplitude and it is given as

here k = constant
A = amplitude
so energy will increase or decrease depends on the amplitude of the wave
So here if we need to check which wave has lower energy then we need to compare the amplitude.
If the amplitude is less then energy must be less
So please check in the figure that which wave out of A and B has lesser amplitude to find out the wave of lesser energy
Answer:
2000 kg m/s
Explanation:
The momentum of an object is a vector quantity whose magnitude is given by

where
m is the mass of the object
v is the velocity of the object
and its direction is the same as the velocity.
In this problem, we have:
- Spaceship 1 has
m = 200 kg (mass)
v = 0 m/s (zero velocity)
So its momentum is

- Spaceship 2 has
m = 200 kg (mass)
v = 10 m/s (velocity)
So its momentum is

Therefore, the combined momentum of the two spaceships is

Answer:
R = 6.67 Ohm's
Explanation:
Resistance is a property of a material that measures the opposition to the flow of current through the material. It is measured in Ohm's.
R = (ρl) ÷ A
where; R is the resistance of the material, A is its cross sectional area, l is its length and ρ is its resistivity.
For the first nichrome wire, resistance is 5 Ohm's.
i.e R = (ρl) ÷ A = 5 Ohm's
For the second nichrome wire, length = 4l, and area of cross section = 3A. The resistance of the second wire can be determined by;
R = (4ρl) ÷ 3A
=
{(ρl) ÷ A}
=
× 5
R = 6.67 Ohm's
Resistance of the second nichrome wire is 6.67 Ohm's.
We calculate the difference between the two velocities,
135 km/h - 35 km/h = 100 km/h
Then, convert the difference into units of m/s
100 km/h x (1000 m/ 1 km) x (1 hour / 3600 s) = 27.78 m/s
Then divide the difference by time.
acceleration = 27.78 m/s / 10.5 s = 2.65 m/s²
(2) In terms of g,
x = 2.65 / 9.80 = 0.27
Therefore, the answer would be,
a = 0.27g