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viktelen [127]
3 years ago
6

Find the distance between the points (-3,2) and (4,-5)

Mathematics
1 answer:
alexandr1967 [171]3 years ago
6 0
You have to use the distance formula. sqrt((x2-x1)^2+(y2-y1)^2) So sqrt((4+3)^2+(-5-2)^2). sqrt(49+49). Sqrt(98). 9.89

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Find the equation of this line
Tatiana [17]
The points are (-4,2) and (3,-4)
using y2-y1/x2-x1
-4-2/3-2
-6/1
slope (m) is -6
to find b part of equation (y=mx+b) plug in point value for x and y
2=-6(-4)+b (multiply -6 and -4)
2=24+b (subtract 24 over)
b=-22
final equation is y=-6x-22
3 0
3 years ago
Can anyone figure this out and explain? Thanks
dezoksy [38]

The deepest point of the lake is -922, so to get to the surface of the lake you would need to add 922 feet.

The deepest point of the lake is 11,542 feet above sea level.


To find the surface of the lake add 922 to 11,542.

11542 + 922 = 12,464 feet

5 0
3 years ago
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The volume of a rectangular prism is 240 cubic centimeters. A rectangular pyramid has the same length, width, and height as the
ValentinkaMS [17]

Answer:

The volume of the pyramid is 80 cubic centimeters.

Step-by-step explanation:

As the formula for the volume of a pyramid is 1/3bh, so if all the dimensions are the same for both figures, just divide the volume of the prism by three to find the volume of the pyramid. If you do this 240÷3=80 or the volume of the pyramid.

5 0
3 years ago
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In the electric currect​ flow, it is found that the resistance​ (measured in the units called​ ohms) offered by a fixed length o
Morgarella [4.7K]
Let x be the resistance of the wire with the larger diameter.
x = (0.456 x (0.01)^2)/(0.0401)^2 = 0.0284 ohms
The answer is 0.0284 ohms.

7 0
3 years ago
22. Find the perimeter and area.
zmey [24]

Answer:

Part 22) The area is A=15a^3b^6\ units^2( and the perimeter is P=10a^2b^4+6ab^2\ unit

Part 24) The area is A=16m^3n\ units^2 and the perimeter is P=24mn\ units    

Part 26) The area is equal to A=9\pi x^6y^{2}\ units^2

Step-by-step explanation:

Part 22) Find the perimeter and area

step 1

The area of a rectangle is equal to

A=LW

we have

L=5(a^2)(b^4)\ units

W=3(a)(b^2)\ units

Remember that

When multiply exponents with the same base, adds the exponents and maintain the base

substitute in the formula

A=(5(a^2)(b^4))(3(a)(b^2))

A=15a^3b^6\ units^2

step 2

The perimeter of a rectangle is equal to

P=2(L+W)

we have

L=5(a^2)(b^4)\ units

W=3(a)(b^2)\ units  

substitute in the formula

P=2(5(a^2)(b^4)+3(a)(b^2))

P=10a^2b^4+6ab^2\ unit

Part 24) Find the perimeter and area

step 1

The area of triangle is equal to

A=\frac{1}{2}bh

where

b=8mn\ units

h=4m^2\ units

Remember that

When multiply exponents with the same base, adds the exponents and maintain the base

substitute the given values

A=\frac{1}{2}(8mn)(4m^2)

A=16m^3n\ units^2

step 2

Find the perimeter

I will assume that is an equilateral triangle (has three equal length sides)

The perimeter of an equilateral triangle is

P=3b

where

b=8mn\ units

substitute

P=3(8mn)

P=24mn\ units

Part 26) Find the area

The area of a circle is equal to

A=\pi r^{2}

where

r=3x^3y\ units

Remember the property

(a^{m})^{n}=a^{m*n}

substitute in the formula the given value

A=\pi (3x^3y)^{2}

A=9\pi x^6y^{2}\ units^2

6 0
3 years ago
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