Answer:
a
Explanation:
bace i have done thos test
Scholarly. Scholarly peer review (also known as refereeing) is the process of subjecting an author's scholarly work, research, or ideas to the scrutiny of others who are experts in the same field, before a paper describing this work is published in a journal, conference proceedings or as a book.
The answers are:
A. DNA replication in the nucleus of a cell
B. From one helix of DNA in a replication process, we get two: The DNA is a double helix and it consists of two strands of specifically connected amino-acids. When the time for replication comes, a set of enzymes unwind the two strands and leave them as a base for additional two strands attaching to them - the green line is an example of that. The free nucleotides - adenine, guanine, thymine and cytosine are left open and the enzyme called DNA-polymerase helps to produce a new strand on the template of the old parental one (one of the blue ones in the picture)
C. By the location on the smaller picture - replication takes place in the nucleus. And the most important hint are the letters A - adenine, G - guanine, T- thymine, and C-cytosine. A connects with T, and G connects with C.
Three questions that focuses on the cause and effect relationship between the genetic code and gene expression, mechanisms of gene regulation and/or the role of DNA segments that is not involved in coding the proteins are:
i. Illustrate the process of translation and explain it with the help of a diagram.
ii. What are codons? Name the stop codons in eukaryotes.
iii. What are exons and introns? Explain what happens to the introns during the process of transcription and translation?
Answer:
The correct answer is - 25%
Explanation:
A cross between true tall pea plant and heterozygous tall pea plant is the cross of tall allele whic is TT and heterozygous which is Tt, so the gametes will be formed would be - T and T by true tall plant and T, and t allele by heterozygous plant.
The Punnett square of this cross is attached with the answer, where 2 heterozygous offspring and two tall offspring produced. In which there is only two recessive short allele formed in this generation out of 8 alleles.
So the probability of short allele would be:
= (2/8) *100
= (1/4) *100
= 25%
