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IgorLugansk [536]
3 years ago
7

Solve equation 2x+3=2x

Mathematics
1 answer:
Digiron [165]3 years ago
3 0
This is an impossible equation.

If you have something and you add 3 to it, how can the result be the same as the original?
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Can you please help me out with a question
Finger [1]

The standard equation of a circle is expressed as

(x - h)^2 + (y - k)^2 = r^2

where

h is the x coordinate of the center of the circle

k is the y coordinate of the center of the circle

r is the radius of the circle(the distance from the center of the circle to the circumference

From the graph,

h = - 1

y = 4

r = 5

By substituting these values into the equation, we have

(x - - 1)^2 + (y - 4)^2 = 5^2

(x + 1)^2 + (y - 4)^2 = 25

Thus, the equation of the circle is

(x + 1)^2 + (y - 4)^2 = 25

8 0
1 year ago
Which terms and 45p^4q have a GCF of 9p^3?
vredina [299]

Answer:

The answer is 18p^3r and 63p^3

Step-by-step explanation:

G.C.F of 18p^3 r and  45p^4q is = 9p^3

18p^3r = 2*3*3*p*p*p*r

45p^4q = 3*3*5*p*p*p*q

Thus the G.C.F is 3*3*p*p*p = 9p^3

G.C.F of  63p^3 and  45p^4q is = 9p^3

63p^3 = 3*3*7*p*p*p

45p^4q = 3*3*5*p*p*p*q

Thus the G.C.F is 3*3*p*p*p = 9p^3

Therefore the answer is 18p^3r and 63p^3....

7 0
3 years ago
Find the product. (do not use spaces in your answer.)<br><br> d ^j · d ^k
bezimeni [28]
d^j\cdot d^k=d^{j+k}
3 0
3 years ago
Read 2 more answers
How many lines of symmetry does this figure have<br> A 1<br> B, 2<br> C. 3<br> D, 4
defon

Answer:

A.1

Step-by-step explanation:

Trapezoids only have one vertical line of symmetry

6 0
3 years ago
Read 2 more answers
Calculate the product of 8/15, 6/5, and 1/3. 
Mariulka [41]
\frac{8}{15} * \frac{6}{5} * \frac{1}{3}

First, I would multiply the last two fractions because they're smaller and easier to work with:

\frac{8}{15} * \frac{6}{5} * \frac{1}{3} = \frac{8}{15} * \frac{6}{15}

Now that we've simplified it, we could multiply these terms and simplify.  An easier method, however, would be to cancel out any common factors among the numerators and denominators before multiplying:

\frac{8}{15} * \frac{6}{15} = \frac{8}{5} * \frac{2}{15}

We can now multiply these terms:

\frac{8}{5} * \frac{2}{15} =  \frac{16}{75}

The <span>product of 8/15, 6/5, and 1/3 is B, 16/75.</span>
5 0
3 years ago
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