Answer:
17. surface area ≈ 441.84
04π m² or 1387.38 m²
18. Ratio of volumes = 8/27
19. volume of the smaller solid = 339 yards³
Step-by-step explanation:
17 .
To find the surface area of the sphere we have to find the radius of the sphere first.
volume of a sphere = 4/3πr³
volume = 1548π m³
r = ?
volume of a sphere = 4/3πr³
1548π = 4/3 × π × r³
multiply both sides by 3/4
1548π × 3/4 = πr³
4644π/4 = πr³
1161π = πr³
divide both sides by π
r³ = 1161
cube root both sides
r = ∛1161
r = 10.5101942
r ≈ 10. 51
surface area of a sphere = 4πr²
surface area = 4 × π × 10.51²
surface area = 4 × 110.4601 × π
surface area = 441.8404π m²
surface area = 441.8404 × 3.14 = 1387.378856 m² ≈ 1387.38 m²
18
If two figure or solid are similar with scale factor or ratio of x/y then the ratio of their volume is (x/y)³. If the ratio of of two similar prism is 2 : 3 the volume will be (2/3)³ = 8/27 .
19
If two solids are similar then the ratio of their surface area is the squared of the scale factor.
121/361 = (x/y)²
square root both sides
x/y = 11/19
If two solids are similar then the ratio of their volume is the cube of the scale factor.
(11/19)³ = a/1747
1331/6859 = a/1747
cross multiply
6859a = 2325257
divide both sides by 6859
a = 2325257/6859
a = 339.008164455
a ≈ 339 yards³
volume of the smaller solid ≈ 339 yards³
9=9m
Next, what you want to do is divide both sides by m to get the variable.
m=1
Answer:
1.07
Step-by-step explanation:
1 To convert to a decimal, divide the percent number by 100.
<h3>107÷100=1.07</h3>
2 Therefore, the decimal form is 1.07
<h3>1.07</h3>
Answer:
Mark point E where the circle intersects segment BC
Step-by-step explanation:
Apparently, Bill is using "technology" to perform the same steps that he would use with compass and straightedge. Those steps involve finding a point equidistant from the rays BD and BC. That is generally done by finding the intersection point(s) of circles centered at D and "E", where "E" is the intersection point of the circle B with segment BC.
Bill's next step is to mark point E, so he can use it as the center of one of the circles just described.
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<em>Comment on Bill's "technology"</em>
In the technology I would use for this purpose, the next step would be "select the angle bisector tool."
10, 20, 30, 40, 50, 60, 70, 80, 90, 100
