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2 years ago

What do you say when you see an empty parrot cage?

Mathematics

1 answer:

irina1246 [14]2 years ago

5 0

Oh no my parrot is missing

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5. Show that the following points are collinear. a) (1, 2), (4, 5), (8,9)

Irina-Kira [14]

Label the points A,B,C

A = (1,2)
B = (4,5)
C = (8,9)

Let's find the distance from A to B, aka find the length of segment AB.

We use the distance formula.

$A = (x_1,y_1) = (1,2) \text{ and } B = (x_2, y_2) = (4,5)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-4)^2 + (2-5)^2}\\\\d = \sqrt{(-3)^2 + (-3)^2}\\\\d = \sqrt{9 + 9}\\\\d = \sqrt{18}\\\\d = \sqrt{9*2}\\\\d = \sqrt{9}*\sqrt{2}\\\\d = 3\sqrt{2}\\\\$

Segment AB is exactly $3\sqrt{2}$ units long.

Now let's find the distance from B to C

$B = (x_1,y_1) = (4,5) \text{ and } C = (x_2, y_2) = (8,9)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(4-8)^2 + (5-9)^2}\\\\d = \sqrt{(-4)^2 + (-4)^2}\\\\d = \sqrt{16 + 16}\\\\d = \sqrt{32}\\\\d = \sqrt{16*2}\\\\d = \sqrt{16}*\sqrt{2}\\\\d = 4\sqrt{2}\\\\$

Segment BC is exactly $4\sqrt{2}$ units long.

Adding these segments gives

$AB+BC = 3\sqrt{2}+4\sqrt{2} = 7\sqrt{2}$

----------------------

Now if A,B,C are collinear then AB+BC should get the length of AC.

AB+BC = AC

Let's calculate the distance from A to C

$A = (x_1,y_1) = (1,2) \text{ and } C = (x_2, y_2) = (8,9)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(1-8)^2 + (2-9)^2}\\\\d = \sqrt{(-7)^2 + (-7)^2}\\\\d = \sqrt{49 + 49}\\\\d = \sqrt{98}\\\\d = \sqrt{49*2}\\\\d = \sqrt{49}*\sqrt{2}\\\\d = 7\sqrt{2}\\\\$

AC is exactly $7\sqrt{2}$ units long.

Therefore, we've shown that AB+BC = AC is a true equation.

This proves that A,B,C are collinear.

For more information, check out the segment addition postulate.

7 0

2 years ago

7 + 4 + -8 + -7 + -5 + 2=?<br><br> Is the answer -7?

balandron [24]

Answer:

Yes

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Please show me how to solve for Xsquared - 21.75X = -15.75. I have the solution but do not know how to solve it.

Andreas93 [3]

$x^2-21.75x=-15.75 \\
x^2-21.75x+15.75=0$

Use the quadratic formula:
$x^2-21.75x+15.75=0 \\ \\
a=1 \\ b=-21.75 \\ c=15.75 \\ b^2-4ac=(-21.75)^2-4 \times 1 \times 15.75=473.0625-63=410.0625 \\ \\
x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}=\frac{-(-21.75) \pm \sqrt{410.0625}}{2 \times 1}=\frac{21.75 \pm 20.25}{2} \\
x=\frac{21.75-20.25}{2} \ \lor \ x=\frac{21.75+20.25}{2} \\
x=\frac{1.5}{2} \ \lor \ x=\frac{42}{2} \\
x=\frac{15}{20} \ \lor \ x=21 \\
x=\frac{3}{4} \ \lor \ x=21 \\
\boxed{x=\frac{3}{4} \hbox{ or } x=21}$

3 0

2 years ago

In 52 days, a ferry transports 42,016 people. The ferry makes 4 trips per day. If the ferry transports the same number of peopl

e-lub [12.9K]

Answer: 600

Step-by-step explanation: sorry if I’m wrong

8 0

2 years ago

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Write the equation in standard form for the circle with center (0, – 10) and radius 6.

Artemon [7]

Answer: