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3 years ago

15

What is the value of the expression?

1 answer:

Dmitry_Shevchenko [17]3 years ago

6 0

-2/5 - (3/7) <span>× (7/10)
</span>= -2/5 - (21/70)
<span>= -2/5 - 3/10
</span><span>= -4/10 - (3/10)
</span>= -7/10

Or

-0.7 (Decimal Form)

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Solve 9/10=z/8 . Round to the nearest tenth.

kompoz [17]

$\boxed {Question}$
$\frac{9}{10} = \frac{z}{8}$

$\boxed {Cross \ multiply}$
$10z = 8 \times 9$

$\boxed {Evaluate}$
$10z = 72$
$z = 72 \div 10$
$z = 7.2$

$\Longrightarrow \bf \ Answer \ : \ z = 7.2$

4 0

3 years ago

Which of the following situations have a net sum of 0? Select three that apply.

statuscvo [17]

Answer:

B,C,E

Step-by-step explanation:

Done this before. A is the first and so on and so forth

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2 years ago

Read 2 more answers

What is the y-intercept of the exponential function? y=2(3)^x

ValentinkaMS [17]

Answer:

( 0 , 2 )

Step-by-step explanation:

To find the x-intercept, substitute in 0 for y and solve for x . To find the y-intercept, substitute in 0 for x and solve for y .

x-intercept(s): None

y-intercept(s): ( 0 , 2 )

3 0

3 years ago

For what value of p the equation [p-3]x²+4[p-3]+4=0

Vikentia [17]

Step-by-step explanation:

(p-3)[x²+4]+4=0

(p-3)[x²+4]=-4

(p-3)=-4/x²+4

p=-4/x²+4+3

p=-4+3(x²+4)/x²+4

p= -4+3x²+12/x²+4

p=8+3x²/x²+4

3 0

3 years ago

If J is the centroid of cde, de=52, fc=15, he=14, find each missing measure

const2013 [10]

Answer:

$DG = 26$

$GE = 26$

$DF = 15$

$CH = 14$

$CE = 28$

Step-by-step explanation:

The figure has been attached, to complement the question.

$DE = 52$

$FC = 15$

$HE = 14$

Given that J is the centroid, it means that J divides sides CD, DE and CE into two equal parts respectively and as such the following relationship exist:

$DF = FC$

$CH = HE$

$DG = GE$

Solving (a): DG

If $DG = GE$ , then

$DE = DG + GE$

$DE = DG + DG$

$DE = 2DG$

Make DG the subject

$DG = \frac{1}{2}DE$

Substitute 52 for DE

$DG = \frac{1}{2} * 52$

$DG = 26$

Solving (b): GE

If $DG = GE$ , then

$GE = DG$

$GE = 26$

Solving (c): DF

$DF = FC$

So:

$DF = 15$

Solving (d): CH

$CH = HE$

$CH = 14$

Solving (e): CE

If $CH = HE$ , then

$CE = CH + HE$

$CE = 14 + 14$

$CE = 28$

7 0

3 years ago