The value of the population of the growth of an endangered birth after 5 years is 1975
<h3>How to determine the population after 5 years?</h3>
The population function is given as:
B(t) = 100 + 3/5t^5
At 5 years, the value of t is 5
So, we have
t = 5
Next, we substitute 5 for t in the equation B(t) = 100 + 3/5t^5
This gives
B(5) = 100 + 3/5 * 5^5
Evaluate the exponent
B(5) = 100 + 3/5 * 3125
Evaluate the product
B(5) = 100 + 1875
Evaluate the sum
B(5) = 1975
Hence, the value of the population of the growth of an endangered birth after 5 years is 1975
Read more about exponential functions at:
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y=5/3x
this is because f(x)=x is one of (identity function) the 12 basic functions and when you multiply it it will shift it on the y axis
If you were to do y=x+5/3 it would make a horizontal shift to the left 5/3
So the unit your on is mostly about knowing the number located in the function that will make the graph shift different ways
<h2>First step/Equation</h2>
Answer:
$362.57
Step-by-step explanation:
A suitable calculator or finance app can find the monthly payment for you. This result comes from a TI-84 calculator.
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The second attachment shows the parameters of the payment function. With 20% down, Anthony is only financing 80% of the price of his car. Of course, there are 12 months in a year, so 4 years worth of payments will be 48 payments. The calculator uses negative values for amounts you pay.
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No doubt your reference material shows you a formula for computing loan payments. One such is ...
A = Pr/(1 -(1+r)^-n)
where r is the monthly interest rate, 0.068/12, and n is the number of payments, 48. The principal amount of the loan, P, will be 19,000×0.80. This formula gives the same result as that shown above and below
The simplest form of -(6x+2y)+4(2x-y) = -2(-x+3y).
It’s 49 is equal to 7 times 7
