Answer:
Below
Explanation:
The balanced equation for h202 = h20 + 02 is:
2H2O2 = 2H20 + O2
The coefficients would be 2
The balanced equation for Na + I2 = NaI is:
2Na + I2 = 2NAI
The coefficients would be 2
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The volume of the flexible container that holds a sample of hydrogen gas at 153 kPa is 1.51L (option B).
<h3>How to calculate volume?</h3>
The volume of a substance can be calculated using the following formula:
P1V1 = P2V2
Where;
- P1 = initial pressure
- P2 = final pressure
- V1 = initial volume
- V2 = final volume
153 × 3 = 304 × V2
459 = 304V2
V2 = 459/304
V2 = 1.51L
Therefore, the volume of the flexible container that holds a sample of hydrogen gas at 153 kPa is 1.51L.
Learn more about volume at: brainly.com/question/2098026
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Answer:
1. Adding hydrogen gas, b. shift to the right
2. Adding a catalyst, c. No effect
3. Decreasing the pressure, a. shift to the left
Explanation:
Hydrogen gas can be rewritten as H2. Whenever you add something to an equilibrium expression, it will shift to whichever side does not have this. So, since the reactant side has 3 moles of H2, adding more H2 to the reaction will shift to the products side, since there is no H2 there.
Adding a catalyst has no effect on equilibrium reactions.
When decreasing the pressure, equilibrium will shift to the side with the greater number of moles of gas. In this case, there are 4 moles of gas on the left, and 2 on the right, so it would shift to the left.