Answer:
I think is c: Product of mixing acids and bases
Tell if Im right
Answer:
pH of the solution is 10.37
Explanation:
![pOH=pkb+log\frac{[salt]}{[base]}](https://tex.z-dn.net/?f=pOH%3Dpkb%2Blog%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bbase%5D%7D)
kb = 
pkb = -log kb
= 
= 3.35
salt is methylammonium bromide and methylamine is base
Substitute the values in the above expression as follows:
![pOH=pkb+log\frac{[salt]}{[base]} \\=3.35+log\frac{0.35}{0.18} \\=3.35+0.28\\=3.63](https://tex.z-dn.net/?f=pOH%3Dpkb%2Blog%5Cfrac%7B%5Bsalt%5D%7D%7B%5Bbase%5D%7D%20%5C%5C%3D3.35%2Blog%5Cfrac%7B0.35%7D%7B0.18%7D%20%5C%5C%3D3.35%2B0.28%5C%5C%3D3.63)
pH = 14 - pOH
= 14 - 3.63
= 10.37
pH of the solution is 10.37
Answer:
(a) When aqueous solution of hydrochloric and ammonia chemically react together then it results in the formation of ammonium chloride.
The reaction equation for this reaction is as follows.
Now, ioni equation for this reaction is as follows.
Cancelling the spectator ions, the net ionic reaction equation is as follows.
(b) When sodium hydroxide chemically reacts with ammonium chloride then it forms ammonia, water and sodium chloride as follows.
Now, the total ionic equation will be as follows.
Cancelling the spectator ions from the above equation. Then the net ionic equation will be as follows.
The equation is one to one so you can use M1V1=M2V2
so
(30ml)(.10M)=(25ml)(x)
x= .12M
The dichloromethane (DCM) has less density than water and also the polarity of water is much more than DCM. So the mixture of water and dichloromethane will always be a heterogeneous mixture. In the mixture dichloromethane will be always up of the water layer. The volume of the separatory funnel which contains the mixture of DCM and water must have to be more than the total volume of the liquids thus the volume of the funnel will be more than (50+50) = 100mL.
The caution have to consider during the separation are-
1. The separatory funnel have to shake well with lid and have to settle down for some times until the two liquid separated.
2. The lid should be open very slowly as the vapor pressure of DCM is more and it will float on the water.
3. After this the stopcock should be opened and slowly the water will come out first followed by DCM.
