Answer: The molecular weight of tris buffer is 121 g/mol
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute
= volume of solution in L
moles of tris buffer =
Now put all the given values in the formula of molality, we get
Therefore, the molecular weight of tris buffer is 121 g/mol
Answer:
60 g
Explanation:
The formula relating mass (<em>m</em>), heat (<em>q</em>), and temperature change (Δ<em>T</em>) is
<em>q = mC</em>Δ<em>T</em> Divide both sides by <em>C</em>Δ<em>T</em> and switch
<em>m</em> = <em>q</em>/(<em>C</em>Δ<em>T</em>)
<em>q</em> = 1260 J
<em>C</em> = the specific heat capacity of water = 4.184 J·K⁻¹g⁻¹
Δ<em>T</em> = <em>T</em>₂ - <em>T</em>₁ = 313 K – 308 K = 5 K
<em>m</em> = 1260/(4.184 × 5)
<em>m</em> = 1260/21
<em>m</em> = 60 g