If you are talking about bonds they are influenced by electronegativity and how many valence electrons they have.
Answer:
Radium is used to produce Radon
Explanation:
Radon is a gas used to treat cancer (certain types).
Explanation:
i guess it's through thousands of research and experiments they conducted
Answer: The standard potential for this cell is +1.49 V at 25C.
Explanation:
![E^0_{[Sn^{2+}/Sn]}=-0.14V](https://tex.z-dn.net/?f=E%5E0_%7B%5BSn%5E%7B2%2B%7D%2FSn%5D%7D%3D-0.14V)
![E^0_{[Ti^{2+}/Ti]}=-1.63V](https://tex.z-dn.net/?f=E%5E0_%7B%5BTi%5E%7B2%2B%7D%2FTi%5D%7D%3D-1.63V)
As titanium has lower reduction potential, it will act as anode and tin will acts as cathode.
Using Nernst equation :
![E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Ti^{2+}]}{[Sn^{2+}]}](https://tex.z-dn.net/?f=E_%7Bcell%7D%3DE%5Eo_%7Bcell%7D-%5Cfrac%7B2.303RT%7D%7BnF%7D%5Clog%20%5Cfrac%7B%5BTi%5E%7B2%2B%7D%5D%7D%7B%5BSn%5E%7B2%2B%7D%5D%7D)
where,
F = Faraday constant = 96500 C
R = gas constant = 8.314 J/mol.K
T = room temperature = 
n = number of electrons in oxidation-reduction reaction = 2
Where both 
are standard reduction potentials.
= standard electrode potential of the cell = 1.49 V
= emf of the cell = ?
Now put all the given values in the above equation, we get:
The correct answer is option C.
1-hexene is an unsaturated hydrocarbon.
2-methylheptane
, 3-ethylpentane and cyclopentane have the suffix -ane, which means they are all alkanes . Alkanes do not have any unsaturation or double bonds.
1-hexene, has the suffix -ene, which means that it is an alkene. Alkanes do have unsaturation or double bonds. As the name indicates, 1-hexene has one double bond.
CH₂=CHCH₂CH₂CH₂CH₃
