Answer:i belive the answer is E = 1/2 mv^2
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Answer:
(a) Distance traveled = 75.3846 m
(b) Velocity of car at that instant will be 14 m/sec
Explanation:
We have given acceleration of the car 
Initial velocity of the cart u = 0 m/sec
(a) According to second equation of motion we know that 
So distance traveled by car 
As the truck is moving with constant speed
So distance traveled by truck 
As the truck overtakes the car
So 


So distance traveled 
(b) From second equation of motion we know that v = u+at
So v = 0+1.3×10.769 = 14 m /sec
Answer:

Explanation:
The acceleration of an object is equal to the change in velocity of the object divided by the time taken for the object to change the velocity:

where:
u is the initial velocity
v is the final velocity
t is the time taken for the velocity to change from u to v
For Ms Jackson in this problem, we have:
u = 6 m/s (initial velocity)
v = 0 m/s (final velocity)
t = 4 s (time elapsed)
Substituting into the equation, we find the acceleration:

And the negative sign indicates that the direction of the acceleration is opposite to the direction of motion.
V = 174 m/s
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hope this helped</span>
p = mv so this question pertains to conservation of momentum.
The momentum of the car is 1320*12 = 15840kgms^-1
For the sake of easiness and the fact negatives are annoying, I will assume east to be positive.
So we know 9.4m - 15840 = (1320+m)*1.5
9.4m - 15840 = 1980+1.5m
Rearranging to solve for m
7.9m = 17820
m = 2255.70 = 2300kg to 2sf