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Natali5045456 [20]
4 years ago
7

What two forces act on falling bodies?

Physics
1 answer:
Alex Ar [27]4 years ago
7 0

The two forces are: Air resistance and gravity.

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3 years ago
A block of cheese is pulled on by a string and slides to the right along a rough surface.
Ulleksa [173]

Answer:

Explanation:

KHAN ACADEMY

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3 years ago
In a circuit with one 12.0 resistor, a current of 0.500 A is flowing. This circuit is powered by a single
Juliette [100K]

Answer:

6 V

Explanation:

In a circuit, the relationship between voltage, current and resistance is given by Ohm's law:

V=RI

where

V is the voltage

R is the resistance

I is the current

In this circuit, we have

R=12.0\Omega is the resistance

I = 0.500 A

so we can find the voltage of the battery by using Ohm's law:

V=(12.0 \Omega)(0.500 A)=6 V

4 0
3 years ago
A girl and her bicycle have a total mads of 42 kg. At the top of the hill her speed is 4 m/s. The hill is 14.3m high and 112m lo
frosja888 [35]

Answer:

13.78 m/s

Explanation:

Given that:

The mass of the girl & her bicycle = 42 kg

The speed at the top of the hilll= 4 m/s

The height of the hill = 14.3 m

The length of the hill (distance) = 112 m

The frictional force = 20 N

To find the speed at the bottom of the hill; we need to carry out the following processes.

The workdone by gravity = mass × acceleration due to  gravity × Δh

= 42 × 9.8 × ( 14.3 - 0 )

= 5885.88 joules

The workdone by the friction = Force × distance = - 20 × 112    (since she is riding down the hill)

The workdone by the friction = -2240 Joules

The initial Kinetic friction = 1/2 mv²

= 1/2 × 42 × 4²

= 336 Joules

The final kinetic energy = Initial Kinetic energy + total work  

The final kinetic energy = (336 + 5885.88 - 2240) Joules

The final kinetic energy = 3981.88   Joules

Using the final kinetic energy =   1/2 mv²

3981.88  = 1/2 × 42 × v²

3981.88  = 21 v²

v² = 3981.88/21

v² =189.61

v = \sqrt{189.61}

v = 13.78 m/s

Therefore, the speed at the bottom = 13.78 m/s

4 0
3 years ago
For a transverse wave, what is a wavefront?
vichka [17]

Explanation:

A wavefront is the long edge that moves, for example, the crest or the trough. Each point on the wavefront emits a semicircular wave that moves at the propagation speed v. These are drawn at a time t later, so that they have moved a distance s = vt.

4 0
3 years ago
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