Answer:
a)1.93 kg-m^2
b) 1.45 kg-m^2
c) = 0
d) 1.15 kg-m^2
Explanation:
mass of the bar M = 4 kg
length of the bar = 2 m
mass of balls m1= m2= 0.3 kg
moment of inertia of bar 
about an axis perpendicular to the bar through its center.
a) MOI of bar + 2×m×(L/2)^2
+ 
now putting the values of m, M and L as above and solving we get
I= 1.93 kg-m^2
b) perpendicular to the bar through one of the balls
= 1.45 kg-m^2
c) parallel to the bar through both balls
zero as the no mass distribution along the parallel to the bar through both balls.
d) parallel to the bar and 0.500 m from it.
I=
putting values and solving we get
1.15 kg-m^2
Answer:
45 W
Explanation:
First of all, we need to find the work done by the person to lift the bag. The work done is given by
where
F = 75.0 N is the force applied
d = 1.50 m is the displacement of the bag
Substituting numbers into the formula,
Now we can find the power used, which is given by
where
t = 2.50 s is the time taken
Again, using W=112.5 J, we find
Answer:
Explanation:
Given
Overall magnification 
One lens magnification is 
suppose the magnification of other lens is 
A compound lens is made up of series of lenses either of same or of different magnification so
is given by
If lens is replaced by 
lens then total magnification is
Try the newtons divided by the force due to gravity which is 104/1.6
Attractive forces between molecules of the same type are called cohesive forces. ... Attractive forces between molecules of different types are called adhesive forces. Such forces cause liquid drops to cling to window panes, for example.
