1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vlada [557]
3 years ago
15

Multiple-Concept Example 4 deals with a situation similar to that presented here. A marble is thrown horizontally with a speed o

f 17.1 m/s from the top of a building. When it strikes the ground, the marble has a velocity that makes an angle of 39 ° with the horizontal. From what height above the ground was the marble thrown?

Physics
1 answer:
kotykmax [81]3 years ago
3 0

Answer:

h = 10m

Explanation:

See it in the pic.

You might be interested in
Describe different types of force in nature at least five​
sineoko [7]

Weathering, Erosion,  deposition, acid rain, precipitation

Explanation:

3 0
3 years ago
Read 2 more answers
Foce that arises due to attraction or repulsion of electronic charges is called​
nika2105 [10]
Electrostatic force
8 0
3 years ago
A section of a parallel-plate air waveguide with a plate separation of 7.11 mm is constructed to be used at 15 GHz as an evanesc
adell [148]

Answer:

the required minimum length of the attenuator is 3.71 cm

Explanation:

Given the data in the question;

we know that;

f_{c_1 = c / 2a

where f is frequency, c is the speed of light in air and a is the plate separation distance.

we know that speed of light c = 3 × 10⁸ m/s = 3 × 10¹⁰ cm/s

plate separation distance a = 7.11 mm = 0.0711 cm

so we substitute

f_{c_1 = 3 × 10¹⁰ / 2( 0.0711  )

f_{c_1 = 3 × 10¹⁰ cm/s / 0.1422  cm

f_{c_1 =  21.1 GHz which is larger than 15 GHz { TEM mode is only propagated along the wavelength }

Now, we determine the minimum wavelength required

Each non propagating mode is attenuated by at least 100 dB at 15 GHz

so

Attenuation constant TE₁ and TM₁ expression is;

∝₁ = 2πf/c × √( (f_{c_1 / f)² - 1 )

so we substitute

∝₁ = ((2π × 15)/3 × 10⁸ m/s) × √( (21.1 / 15)² - 1 )

∝₁ = 3.1079 × 10⁻⁷

∝₁ = 310.79 np/m

Now, To find the minimum wavelength, lets consider the design constraint;

20log₁₀e^{-\alpha _1l_{min = -100dB

we substitute

20log₁₀e^{-(310.7np/m)l_{min = -100dB

l_{min = 3.71 cm

Therefore, the required minimum length of the attenuator is 3.71 cm

6 0
3 years ago
A harmonic wave is traveling along a rope. It is observed that the oscillator that generates the wave completes 37.6 vibrations
tangare [24]

Answer:

\lambda = 25.79\ cm

Explanation:

given,

Wave vibrates = 37.6

time = 27.9 s

maximum distance travel = 450 cm

time = 11.3 s

wavelength = ?

frequency of wave

f=\dfrac{37.6}{27.9}

f = 1.35 Hz

Speed of wave

v = \dfrac{450}{11.3}

v = 39.82 cm/s

wavelength of wave

v = fλ

\lambda =\dfrac{v}{f}

\lambda =\dfrac{34.82}{1.35}

\lambda = 25.79\ cm

Hence, wavelength of the wave is equal to 25.79 cm.

8 0
3 years ago
On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball with a golf club improvised from a tool. The free-f
aliya0001 [1]

Answer:

15.3 s and 332 m

Explanation:

With the launch of projectiles expressions we can solve this problem, with the acceleration of the moon

    gm = 1/6 ge

    gm = 1/6  9.8 m/s² = 1.63 m/s²

We calculate the range

    R = Vo² sin 2θ  / g

    R = 25² sin (2 30) / 1.63

    R= 332 m

We will calculate the time of flight,

   Y = Voy t – ½ g t2  

   Voy = Vo sin θ

When the ball reaches the end point has the same initial  height Y=0

0 = Vo sin  t – ½  g t2

0 = 25 sin (30)  t – ½ 1.63 t2

0= 12.5 t –  0.815 t2

We solve the equation

0= t ( 12.5 -0.815 t)

 t=0 s

t= 15.3 s

The value of zero corresponds to the departure point and the flight time is 15.3 s

Let's calculate the reach on earth

R2 = 25² sin (2 30) / 9.8

R2 = 55.2 m

R/R2 = 332/55.2

R/R2 = 6

Therefore the ball travels a distance six times greater on the moon than on Earth

5 0
3 years ago
Other questions:
  • Please help me
    9·1 answer
  • PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
    7·1 answer
  • The pressure of a box pushes down on the floor is 50 Pa if the box weighs 400 N what is the area of the base of the box
    12·1 answer
  • 25 POINTS<br> In outerspace, do Newton's laws still apply?<br> A) yes <br> B) No
    10·2 answers
  • Explain why you can hear two people talking even after they walk around a corner.
    5·2 answers
  • What key ingredient in the modern condensation theory was missing or unknown in the nebula theory?
    7·1 answer
  • Hi can you help me with this please?
    6·1 answer
  • Select all the correct answers.
    5·1 answer
  • If two cells out of n number of cells each of internal resistance ’r’ are wrongly connected in series, then total resistance of
    14·2 answers
  • One component of a magnetic has a magnitude of 0.045T and points along the +r axis, while the other component has a magnitude of
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!