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Vlada [557]
3 years ago
15

Multiple-Concept Example 4 deals with a situation similar to that presented here. A marble is thrown horizontally with a speed o

f 17.1 m/s from the top of a building. When it strikes the ground, the marble has a velocity that makes an angle of 39 ° with the horizontal. From what height above the ground was the marble thrown?

Physics
1 answer:
kotykmax [81]3 years ago
3 0

Answer:

h = 10m

Explanation:

See it in the pic.

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P=(2 nm, 8mn)

Explanation:

Given :

Position of positively charged particle at origin, O=(0\ nm,0\ nm)

Position of desired magnetic field, D\equiv(1\ nm,8\ nm)

Magnitude of desired magnetic field, E=0\ N.C^{-1}

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<u>We know the distance between the two Cartesian points is given as:</u>

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\frac{1}{4\pi.\epsilon_0} \times \frac{q}{r^2 } =\frac{1}{4\pi.\epsilon_0} \times \frac{q}{r^2 }

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as we know that the electric field lines emerge radially outward of a positive charge so the second charge will be at equally opposite side of the  given point.

assuming that the second charge is placed at (x,y) nano-meters.

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