Multiple-Concept Example 4 deals with a situation similar to that presented here. A marble is thrown horizontally with a speed o
f 17.1 m/s from the top of a building. When it strikes the ground, the marble has a velocity that makes an angle of 39 ° with the horizontal. From what height above the ground was the marble thrown?
1 answer:
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Answer:
Explanation:
We can use the conservation of the angular momentum.
Now the Inertia is I(professor_stool) plus mR², that is the momentum inertia of a hoop about central axis.
So we will have:
Now, we just need to solve it for ω.
I hope it helps you!