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Veronika [31]
3 years ago
5

Boyle's law states that gas volume is Boyle's law states that gas volume is inversely proportional to temperature. directly prop

ortional to pressure. inversely proportional to pressure. directly proportional to temperature. both directly proportional to pressure and directly proportional to temperature.
Chemistry
2 answers:
ankoles [38]3 years ago
8 0

<u>Answer:</u> Boyle's law states that gas volume is inversely proportional to pressure.

<u>Explanation:</u>

Boyle's law is one of the law used to determine the Ideal Gas equation.

This law states that pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles

Mathematically,

P\propto \frac{1}{V}          (at constant temperature and number of moles)

The above expression can also be written as:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume of the gas

P_2\text{ and }V_2 are final pressure and volume of the gas

Hence, Boyle's law states that gas volume is inversely proportional to pressure.

erik [133]3 years ago
6 0

Answer:

Directly proportional to temperature.

Inversely proportional to  pressure.

Explanation:

As the temperature increases so does the volume.

As the pressure increases the volume decreases.

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arsen [322]

Answer:

1.8066e+24 is the answer

3 0
3 years ago
If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 Liters, what is the temperature in Kelvin(K)
kvv77 [185]

Answer:

205 K (to 3 significant figures)

Explanation:

Assuming that 4 moles of the gas behaves like an ideal gas and obey the kinetic molecular theory.

Let's apply the ideal gas law, pV= nRT.

Here p denotes the pressure of the gas, V is for volume, n is the number of moles of the gas, R is the universal gas constant and T is the temperature.

Substitute the given information into the equation:

5.6 atm ×12 L= 4 mol ×R ×T

Since pressure is in atm and volume is in L, we can use R= 0.08206 L atm K⁻¹ mol⁻¹.

5.6 atm ×12 L= 4 mol ×0.08206 L atm K⁻¹ mol⁻¹ ×T

T= 67.2 ÷0.32824

T= 204.73 (5 s.f.)

T= 205 K (3 s.f.)

4 0
2 years ago
How many milliliters of water will be created from a combustion reaction with 9.32×10 22nd power of ethanol molecules. Assume de
PolarNik [594]

Answer:

8.38 mL

Explanation:

1- The combustion reaction of ethanol (C2H5OH) in the presence of oxygen (O2) has as reaction products carbon dioxide (CO2) and water (H2O), the equation equaled is:

<em>C2H5OH (l) + 3 O2 (g) CO2 2 CO2 (g) + 3 H2O (l) </em>

2- By establishing the stoichiometric relationship between ethanol and water, you can calculate the number of molecules that will be created from the initial amount of alcohol molecules:

6,022x10 23 molecules of C2H5OH (1 mol) ___ 3 x 6,022x10 23 molecules of H2O (3 moles)

9.32x10 22 C2H5OH molecules _____ X = 2.80x10 23 H2O molecules

<em>Calculation: </em>

9.32x10 22 x (3 x 6.022x10 23) / 6.022x10 23 = 2.80x10 23 H2O molecules

3- Once the number of water molecules formed is obtained, with the molar mass the mass can be determined:

6.022x10 23 H2O molecules _____ 18.02 g

2.80x10 23 molecules of H2O _____ X = 8.38 g of H2O

<em>Calculation: </em>

2.80x10 23 x 18.02 g / 6.022x1023 = 8.38 g of H2O

4- Finally, having the density of water, you can calculate the volume that formed:

d = m / V  --> V = m / d

V = 8.38 g / 1.00 mL = 8.38 mL

The answer is that 8.38 mL of water is formed

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3 0
3 years ago
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