Answer:
ICE Table Figure
a. 67.37 g 
b. 35.62 g 
c. 58.61 g
Explanation:
For the <u>ICE table </u>we have to keep in mind that we have 4 moles of
and 1 mol of
and the reactives are consumed, so for
we will have -4X and for
we will have -X. Follow the same logic we will have -4X for
.
a. <u>Mass of the product</u>
Molar mass of
= 256.52 g/mol
Molar mass of
=70.9 g/mol
Molar mass of
=135.03 g/mol
We have to find the limiting reagent in the reaction:



Divide by the coefficients in the balanced reaction:


The limiting reagent would be 
Now is posible to calculate the amount of
produced:

b. <u>Mass in excess</u>


C. <u>87%Yield</u>

pH = - log[acid] = -log [H+]
pH= -log[10] = 1
Thus, pH is 1
if pH is 7, the solution is neutral and if pH is greater than 7 the solution is basic and if it is less than 7 the solution is acidic.
This solution have pH = 1, thus the solution is acidic.
Answer: The IUPAC name of compound is
6-Ethyl-2-Octene.
Explanation:First of all draw a straight chain of 8 carbon atoms.
Make a double bond between carbon number 6 and 7 numbering from left.
Add ethyl group at position 3 starting from left.
The structure sketched is attached below,
According to rules the longest chain containing a double bond is selected. Numbering is started from the end to which double bond is nearer. So, in our case the double bond starts at carbon 2, hence parent name of compound is 2-Octene. Then the substituent at position 6 is named.
The correct answer would be B: 4.