<h3>
Answer:</h3>
5.6 L
<h3>
Explanation:</h3>
We are given;
- Initial volume, V1 = 3.5 L
- Initial pressure, P1 = 0.8 atm
- Final pressure, P2 = 0.5 atm
We are required to calculate the final volume;
- According to Boyle's law, the volume of a fixed mass of a gas and the pressure are inversely proportional at a constant temperature.
- That is; P α 1/V
- Mathematically, P=k/V
- At two different pressure and volume;
P1V1 = P2V2
In this case;
Rearranging the formula;
V2 = P1V1 ÷ P2
= (0.8 atm × 3.5 L) ÷ 0.5 atm
= 5.6 L
Therefore, the resulting volume is 5.6 L
Answer:
Main group elements, the transition metals, the lanthanides, and the actinides.
Explanation:
Answer:
The answer to your question is empirical formula Al₃O₉S
Explanation:
Data
Al = 31.5 %
O = 56.1 %
S = 12.4 %
Process
1.- Look for the atomic masses of the elements
Al = 27 g
O = 16
S = 32
2.- Represent the percentages as grams
Al = 31.5 g
O = 56.1 g
S = 12.4 g
3.- Convert these masses to moles
27 g of Al ----------------- 1 mol
31.5 g ---------------------- x
x = 1.17 moles
16 g of O ---------------- 1 mol
56.1 g of O ------------- x
x = 3.5 mol
32 g of S --------------- 1 mol
12.4 g of S ------------- x
x = 0.39 moles
4.- Divide by the lowest number of moles
Al = 1.17 / 0.39 = 3
O = 3.5 / 0.39 = 8.9 ≈ 9
S = 0.39 / 0.39 = 1
5.- Write the empirical equation
Al₃O₉S
Answer:
84.75°C is the boiling point of water at an elevation of 7000 meter.
Explanation:
Rate of change of pressure = 19.8 mmHg/1000 ft
1 foot = 
meter
Pressure change for every 1 m = 0.065 mmHg × 1= 0.065 mmHg
Elevation Pressure
0 m 760 mmHg
1000 m 695 mmHg
2000 m 630 mmHg
Pressure drop at the elevation of 7000 m: 
Pressure at 7000 m = 760 mmHg - 455mmHg = 305 mmHg
The boiling point of water decreases 0.05°C for every 1 mmHg drop in atmospheric pressure.
At 7000 meter elevation the boiling of water will be :
Boiling point of water at 7000 meter elevation :
84.75°C is the boiling point of water at an elevation of 7000 meter.
