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ozzi
3 years ago
6

What is the gravitational force between two masses of 1 kg each kept at the distance of 1m?​

Chemistry
1 answer:
Eddi Din [679]3 years ago
6 0

Answer:

<h2>F=Gm1m2r=G×1×11=G</h2>

Explanation:

<h2>______________________________</h2>

<h2>(*˘︶˘*).。*♡</h2>

<h2><em><u>PLEASE</u></em><em><u> MARK</u></em><em><u> ME</u></em><em><u> BRAINLIEST</u></em><em><u> AND</u></em><em><u> FOLLOW</u></em><em><u> M</u></em><em><u> E</u></em><em><u> LOTS</u></em><em><u> OF</u></em><em><u> LOVE</u></em><em><u> FROM</u></em><em><u> MY</u></em><em><u> HEART</u></em><em><u> AND</u></em><em><u> SOUL</u></em><em><u> DARLING</u></em><em><u> TEJASWINI</u></em><em><u> SINHA</u></em><em><u> HERE</u></em><em><u> ❤️</u></em></h2>
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2 years ago
How much energy has your body used, in joules, if your health
Verdich [7]

Answer:

  1. 1,882.8 joules
  2. 83.652 calories

Explanation:

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Amount in calories = 450 calories

Amount in joules = 3.5 × 100 joules

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  2. Change in calories

Computation:

We know that,

1 calories = 4.184 joules

So,

Amount in calories = 450 calories

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8 0
3 years ago
How many moles of gas will occupy 3.5 L container at 315 K, if the pressure is 2.1 atm?
Ratling [72]

Answer: 3 moles

Explanation:

Using the ideal gas equation; PV = nRT

P= Pressure= 2.1 Atm  V= Volume = 3.5L  T= Temperature = 315K

n= no of moles

R= Gas constant = 0.08206 L .atm. mol-1 . K-1

Making 'n' the subject of the formular, we then have;

n = PV / RT

   = 2.1 Atm x 3.5L /  0.08206 L .atm. mol-1 . K-1 x 315K

   =  7.35 / 25.849

   =  0.28  approx  3moles

4 0
3 years ago
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