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2 years ago

Devaughn is 12 years younger than sydney. the sum of thier ages is 50 what is syndys age?

Mathematics

2 answers:

likoan [24]2 years ago

7 0

Answer:

Step-by-step explanation:

50/2

25 25

13 25

+12

25 25

oee [108]2 years ago

7 0

Answer:

Devaughn is 12 years younger then sydney.

Step-by-step explanation:

Devaughn is 12 years younger then sydney.

THEIR** Ages together equal 50 in total.

So 38 would have to be Devaughn's age while Sydney's age would be 50.

38+12= 50

The sum needed to be 50 so the sum is 50 and Devaughn is 12 years younger.

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Given: ABC is a right triangle with right angle C. AC=15 centimeters and m∠A=40∘ . What is BC ? Enter your answer, rounded to th

konstantin123 [22]

In order to answer this question, the figure in the first picture will be helpful to understand what a right triangle is. Here, a right angle refers to $90\°$ .

However, if we want to solve the problem we have to know certain things before:

In the second figure is shown a general right triangle with its three sides and another given angle, we will name it $\alpha$ :

The side opposite to the right angle is called The Hypotenuse (h)

The side opposite to the angle $\alpha$ is called the Opposite (O)

The side next to the angle $\alpha$ is called the Adjacent (A)

So, going back to the triangle of our question (first figure):

The Hypotenuse is AB

The Opposite is BC

The Adjacent is AC

Now, if we want to find the length of each side of a right triangle, we have to use the Pythagorean Theorem and Trigonometric Functions:

Pythagorean Theorem

$h^{2}=A^{2} +O^{2}$ (1)

Trigonometric Functions (here are shown three of them):

Sine: $sin(\alpha)=\frac{O}{h}$ (2)

Cosine: $cos(\alpha)=\frac{A}{h}$ (3)

Tangent: $tan(\alpha)=\frac{O}{A}$ (4)

In this case the function that works for this problem is cosine (3), let’s apply it here:

$cos(40\°)=\frac{AC}{h}$

$cos(40\°)=\frac{15}{h}$ (5)

And we will use the Pythagorean Theorem to find the hypotenuse, as well:

$h^{2}=AC^{2}+BC^{2}$

$h^{2}=15^{2}+BC^{2}$ (6)

$h=\sqrt{225+BC^2}$ (7)

Substitute (7) in (5):

$cos(40\°)=\frac{15}{\sqrt{225+BC^2}}$

Then clear BC, which is the side we want:

${\sqrt{225+BC^2}}=\frac{15}{cos(40\°)}$

${{\sqrt{225+BC^2}}^2={(\frac{15}{cos(40\°)})}^2$

$225+BC^{2}=\frac{225}{{(cos(40\°))}^2}$

$BC^2=\frac{225}{{(cos(40\°))}^2}-225$

$BC=\sqrt{158,41}$

$BC=12.58$

Finally $BC$ is approximately 13 cm

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3 years ago

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Plz help me pls

NikAS [45]

Answer:

8hr=480min

30min=1800sec

15hr=900min

5yr=1825d

Step-by-step explanation:

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2 years ago

7. What is the value of x? −4x − 6 = −34 A. −10 B. −7 C. 7 D. 10

galben [10]

-4x - 6 = -34

First, add '6' to both sides.
$-4x = -34 + 6$
Second, subtract '-34 + 6' to get '-28'.
$-4x = -28$
Third, divide both sides by '-4', leaving the 'x' by itself.
$x = \frac{-28}{-4}$
Fourth, simplify the fraction into a negative.
$x = \frac{28}{4}$
Fifth, how many times can 4 go into 28? Divide. 28 ÷ 4 = 7.
$x = 7$

Answer: C) x = 7

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2 years ago

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Varvara68 [4.7K]

. 5 is Rational
Square root 24 is irrational
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2 years ago

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Volgvan

A. The perimeter of quadrilaterals are same when x=2.

B. The area of quadrilaterals are same when x=4.6

Step-by-step explanation:

A. Perimeter of the quadrilaterals must be equal.

Perimeter of square is 4a.
where, a = 6
Perimeter of rectangle is 2(l+b).
where, l = 2 and b = (3x+4)

Perimeter of square = Perimeter of rectangle

4(6) = 2(2+3x+4)

⇒ 24 = 2(3x+6)

⇒ 24 = 6x + 12

⇒ 6x = 12

⇒ x = 12/6

x = 2

For x=2, the perimeters of both the quadrilaterals are same.

B. Area of the quadrilaterals must be equal.

Area of square is a².
where, a = 6.
Area of rectangle is l $\times$ b.
where, l = 2 and b = (3x+4)

Area of square = Area of rectangle

(6)² = 2(3x+4)

36 = 6x+8

6x = 28

x = 28/6

x = 4.6

For x=4.6, the area of both the quadrilaterals are same.

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2 years ago

Devaughn is 12 years younger than sydney. the sum of thier ages is 50 what is syndys age?​

Devaughn is 12 years younger than sydney. the sum of thier ages is 50 what is syndys age?