Ask question

Ask question

All categories

3 years ago

10

How many thirds are in 8/3? Lol this is easy

2 answers:

Zigmanuir [339]3 years ago

6 0

The answer is 2.6 so 2 3/6

Archy [21]3 years ago

3 0

Hello

There are 8 thirds in 8/3 if you put 8/3 in the calculator it is 2.66 repeated or 2.6666666667

hope this helps

plz mark me as brainliest

You might be interested in

Simplify the square root of 27x^12/300x^8

Darina [25.2K]

The first thing we are going to do is rewrite the expression correctly.
We have:
root (27x ^ 12 / 300x ^ 8)
Rewriting:
root ((27/300) * (x ^ 12 / x ^ 8))
root ((9/100) * (x ^ (12-8)))
root ((9/100) * (x ^ (4)))
root ((9/100) * (x ^ (4)))
3 * x ^ 2 * root ((1/100)
(3 * x ^ 2) / 10
(3/10) * (x ^ 2)
Answer:
(3/10) * (x ^ 2)

6 0

4 years ago

Read 2 more answers

Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and ro

Helga [31]

Answer:

Part 1) The shape is a trapezoid

Part 2) The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

Part 3) The area is $937.5\ units^2$

Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

The shape is a trapezoid

see the attached figure

step 2

Find the perimeter

we know that

The perimeter of the trapezoid is equal to

$P=AB+BC+CD+AD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

we have

A(-28,2),B(-21,-22)

substitute in the formula

$d=\sqrt{(-22-2)^{2}+(-21+28)^{2}}$

$d=\sqrt{(-24)^{2}+(7)^{2}}$

$d=\sqrt{625}$

$d_A_B=25\ units$

Find the distance BC

we have

B(-21,-22),C(27,-8)

substitute in the formula

$d=\sqrt{(-8+22)^{2}+(27+21)^{2}}$

$d=\sqrt{(14)^{2}+(48)^{2}}$

$d=\sqrt{2,500}$

$d_B_C=50\ units$

Find the distance CD

we have

C(27,-8),D(-4,9)

substitute in the formula

$d=\sqrt{(9+8)^{2}+(-4-27)^{2}}$

$d=\sqrt{(17)^{2}+(-31)^{2}}$

$d=\sqrt{1,250}$

$d_C_D=25\sqrt{2}\ units$

Find the distance AD

we have

A(-28,2),D(-4,9)

substitute in the formula

$d=\sqrt{(9-2)^{2}+(-4+28)^{2}}$

$d=\sqrt{(7)^{2}+(24)^{2}}$

$d=\sqrt{625}$

$d_A_D=25\ units$

Find the perimeter

$P=25+50+25\sqrt{2}+25$

$P=(100+25\sqrt{2})\ units$

simplify

$P=25(4+\sqrt{2})\ units$ ----> exact value

$P=135.4\ units$

therefore

The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

step 3

Find the area

The area of trapezoid is equal to

$A=\frac{1}{2}[BC+AD]AB$

substitute the given values

$A=\frac{1}{2}[50+25]25=937.5\ units^2$

4 0

3 years ago

What’s the fraction fro 5/12+(-7/12)

Veseljchak [2.6K]

Answer:

-.167= -1/6

Step-by-step explanation:

5/12+(-7/12)

=(5 × 12) + (-7 × 12)

_______________

12 × 12

=-24/144

= -24 ÷ 24

________

144 ÷ 24

= - 1

_______

6

4 0

3 years ago

Solve for the variable: 2x - 28 = 16

svlad2 [7]

2x = 44
44/2 = x
X= 22

4 0

3 years ago

Read 2 more answers

If y varies directly with x and y=2 when x=15. Find x when y=8.

andreyandreev [35.5K]

Since the two numbers vary directly, if Y is quadrupled, X will do the same. 2 times 4 is 8, 15 times 4 is 60.

X = 60.

Hope that helps!! :)

8 0

3 years ago

Read 2 more answers