Perimeter= 2 ( length + width)
2×(12+6)
2×18
=36
Answer:
4y²−38y−20
Step-by-step explanation:
(y−10)(4y+2)
=(y+−10)(4y+2)
=(y)(4y)+(y)(2)+(−10)(4y)+(−10)(2)
=4y²+2y−40y−20
=4y²−38y−20
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Answer:
y -11 = 2(x -3)
Step-by-step explanation:
The slope of the given line is the x-coefficient: 2. The parallel line will have the same slope.
When you know the slope and a point on the line, it is convenient to use the point-slope form of the equation of a line:
y -k = m(x -h) . . . . . . line with slope m through point (h, k)
Your line's equation is ...
y -11 = 2(x -3)
We know that the perimeter of a rectangle is 2(width)+2(length). We can multiply the length by 2 to find out how much remaining fencing we have, then divide that number by 2 to find the width.
15.5*2=31
170.5-31=139.5
139.5/2=69.75
A possible width is 69.75 feet.