The number of quarters she have 11.
<h3>What is a system of equations?</h3>
A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.
Let consider y = quarters; x = dimes
We know that there are 3 times as many dimes as quarters. So we can state that x = 3y.
Then, we say that 25y + 10x = 605
(Value of coin * amount of coins)
Then we substitute x=3y into the equation, yielding:
25y + 10(3y) = 605
25y + 30y = 605
55y = 605
605/55 = 11 = y
Therefore, the number of quarters she have 11.
Learn more about equations here;
brainly.com/question/10413253
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Answer:
The parent graph is translated 2 to the left and up 6 units.
Step-by-step explanation:
The +2 moves the parent 2 units to the left and the + 6 moves it up 6 units.
Answer:
P = 16
Step-by-step explanation:
Given
5W = 2P + 3R ← substitute W = 4 and R = - 4 into the equation
5(4) = 2P + 3(- 4), that is
20 = 2P - 12 ( add 12 to both sides )
32 = 2P ( divide both sides by 2 )
16 = P
<span>280
I'm assuming that this question is badly formatted and that the actual number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts. So let's take each course by itself.
You can choose 1 of 7 appetizers. So we have
n = 7
After that, you chose an entre, so the number of possible meals to this point is
n = 7 * 10 = 70
Finally, you finish off with a dessert, so the number of meals is:
n = 70 * 4 = 280
Therefore the number of possible meals you can have is 280.
Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is
n = 77 * 1010 * 44 = 3421880
But I believe that it's highly unlikely that the numbers in this problem are correct. Just imagine the amount of time it would take for someone to read a menu with over a thousand entres in it. And working in that kitchen would be an absolute nightmare.</span>
Answer:
Explanation:
<u />
<u>1. First find the density of your chain</u>
- Volume = displaced water volume
= Volume of Final level of water - initial level of water
= 20 ml - 15 ml = 5 ml
- Density = 66.7g / 5 ml = 13.34 g/ml
<u />
<u>2. Second, write the denisty of the chain as the weighted average of the densities of the other metals:</u>
Mass of gold × density of gold + mass of other metals × density of other metals, all divided by the mass of the chain.
Calling x the amount of gold, then the amount of other metals is 66.7 - x:
Then, there are 26.47 grams of gold in 66.7 grams of chain, which yields a percentage of:
- (26.47 / 66.7) × 100 = 39.7%
