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saveliy_v [14]
4 years ago
13

How many moles of pcl5 can be produced from 28.0 g of p4 (and excess cl2)?

Chemistry
1 answer:
BARSIC [14]4 years ago
5 0
P₄ + 10Cl₂ ---> 4PCl₅
stoichiometry of P₄ to PCl₅ is 1:4
number of moles of P₄ reacted - 28.0 g / 124 g/mol = 0.22 mol 
Cl₂ is in excess therefore P₄ is the limiting reactant, amount of product formed depends on amount of limiting reactant present 
according to molar ratio of 1:4
number of PCl₅ moles formed  -0.22 mol x 4 = 0.88 mol 
0.88 mol of PCl₅ is formed 

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Number of coulombs of positive charge in 250cm^3 water is 1.3×10^7 C

The volume of 250 cm^3 corresponds to a mass of 250 g since the density of water is 1.0 g/cm^3

This mass corresponds to 250/18 = 14 moles since the molar mass of water is 18. There are ten proton (each with charge q = +e) in each molecule of H_{2}O So,

Q = 14NA  q =14(6.02×10^23)(10)(1.60×10^−19C) = 1.3×10^7 C.

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3 0
1 year ago
If 33.6 grams of kcl are dissolved in 192 grams of water, what is the concentration of the solution in percent by mass? 21.2% kc
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Ms ( mass of solute): 33,6g
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__________________
C = ms/mss × 100%
C = 33.6/225.6 × 100%
C = 14,89% ≈ 14,9%

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4 0
3 years ago
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7 0
3 years ago
Give all possible ml values for orbitals that have each of the following:<br> (a) l = 3;
Angelina_Jolie [31]

At l = 3, ml =+3,+2,+1,0,-1,-2,-3

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8 0
2 years ago
2. What is the change in the atomic number when an atom emits an alpha particle? (1 point)
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