Answer:
The resulting molarity is 6M.
Explanation:
A dilution consists of the decrease of concentration of a substance in a solution (the higher the volume of the solvent, the lower the concentration).
We use the formula for dilutions:
C1 x V1 = C2 x V2
12 M x 0,5L = C2 x 1,0 L
C2= (12 M x 0,5 L)/1,0 L
<em>C2= 6 M</em>
The indirect result of contaminants from commercial farming is algae.
<h3>What is Contaminant?</h3>
Contaminant is a substance either chemical, physical that is very toxic or harmful to living organisms, when it is released into air, water, soil or food.
Contaminant are poisionus substance that are not deliberately or are deliberately introduced to space . This contaminants make things impure and they are highly poisionus.
Therefore, The indirect result of contaminants from commercial farming is algae.
Learn more about contaminant below.
brainly.com/question/465199
Answer:
The chemical formula for ammonium hypochlorite is NH4ClO.
The chemical formula for ammonium nitrate is NH4NO3.
Explanation:
These two are correct
Answer: The correct answer is -297 kJ.
Explanation:
To solve this problem, we want to modify each of the equations given to get the equation at the bottom of the photo. To do this, we realize that we need SO2 on the right side of the equation (as a product). This lets us know that we must reverse the first equation. This gives us:
2SO3 —> O2 + 2SO2 (196 kJ)
Remember that we take the opposite of the enthalpy change (reverse the sign) when we reverse the equation.
Now, both equations have double the coefficients that we would like (for example, there is 2S in the second equation when we need only S). This means we should multiply each equation (and their enthalpy changes) by 1/2. This gives us:
SO3 —>1/2O2 + SO2 (98 kJ)
S + 3/2O2 —> SO3 (-395 kJ)
Now, we add the two equations together. Notice that the SO3 in the reactants in the first equation and the SO3 in the products of the second equation cancel. Also note that O2 is present on both sides of the equation, so we must subtract 3/2 - 1/2, giving us a net 1O2 on the left side of the equation.
S + O2 —> SO2
Now, we must add the enthalpies together to get our final answer.
-395 kJ + 98 kJ = -297 kJ
Hope this helps!