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Nikitich [7]
3 years ago
11

Two elements with the same number of protons but a different number of 2 points

Chemistry
1 answer:
notsponge [240]3 years ago
3 0

Answer: isotopes

Explanation: I remember this from when I took honors chemistry, they are know as isotopes.

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I am finding the formula of a compound that has 60% Carbon, 32% Oxygen, and 8% Hydrogen. Although, when it comes to actually cre
nataly862011 [7]

Answer:

Explanation:

To determine the molecular formula of the compound, the empirical formula must be determined first. To determine the empirical formula, the percentage of each constituent is divided by its molar mass. This is shown below

Carbon = 60/12 = 5

Oxygen = 32/16 = 2

Hydrogen = 8/1 = 8

The next step is to divide each ratio by the smallest value. The smallest value is 2. It becomes

Carbon = 5/2 = 2.5

It is approximated to 3

Oxygen = 2/2 = 1

Hydrogen = 8/2 = 4

Therefore, the empirical formula is

C3H4O

From the given relative molecular mass of the compound, the molecular formula can be determined

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Diffusion is the movement of water between the cell membrane. <br>O True <br>O False​
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Which of the following is ONE of the signs of a chemical change
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What is meant by collision theory?
Tcecarenko [31]

Answer:

The collision theory states that a chemical reaction can only occur between particles when they collide (hit each other).

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4 0
2 years ago
The solubility product of PbI2 is 7.9x10^-9. What is the molar solubility of PbI2 in distilled water?
Agata [3.3K]

<u>Answer:</u> The molar solubility of PbI_2 is 1.25\times 10^{-3}mol/L

<u>Explanation:</u>

Solubility is defined as the maximum amount of solute that can be dissolved in a solvent at equilibrium.

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The balanced equilibrium reaction for the ionization of calcium fluoride follows:

PbI_2\rightleftharpoons Pb^{2+}+2I^-

                s       2s

The expression for solubility constant for this reaction will be:

K_{sp}=[Pb^{2+}][I^-]^2

We are given:

K_{sp}=7.9\times 10^{-9}

Putting values in above equation, we get:

7.9\times 10^{-9}=(s)\times (2s)^2\\\\7.9\times 10^{-9}=4s^3\\\\s=1.25\times 10^{-3}mol/L

Hence, the molar solubility of PbI_2 is 1.25\times 10^{-3}mol/L

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