There are 17.97 moles of calcium chloride would react with 5. 99 moles of aluminum oxide .
The balanced chemical equation between reaction between calcium chloride and aluminum oxide is given as,
→ 
The molar ratio of above reaction is 3:1
It means 3 moles of calcium chloride is require to react one mole of aluminum oxide.
The number of moles of calcium chloride requires to react with 5. 99 moles of aluminum oxide = 3 × 5. 99 = 17.97 moles
The equation in which number of atoms of elements in reactant side is equal to the number of atoms of elements in product side is called balanced chemical equation .
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Avogadro's law states that in a mole of any substance, there are
atoms. This means that in the given sample, there are

- The atomic mass of sulfur is 32.06 amu.
- The atomic mass of oxygen is 15.9994 amu.
So, the atomic mass of sulfur dioxide is

Therefore, the mass is:

Question:
A chemistry student needs of 10 g isopropenylbenzene for an experiment. He has available 120 g of a 42.7% w/w solution of isopropenylbenzene in acetone. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.
Answer:
The answer to the question is as follows
The mass of solution the student should use is 23.42 g.
Explanation:
To solve the question we note the following
A solution containing 42.7 % w/w of isopropenylbenzene in acetone has 42.7 g of isopropenylbenzene in 100 grams of the solution
Therefore we have 10 g of isopropenylbenzene contained in
100 g * 10 g/ 42.7 g = 23.42 g of solution
Available solution = 120 g
Therefore the quantity to used from the available solution = 23.42 g of the isopropenylbenzene in acetone solution.
The unit 'mW' means milliwatts. It is a unit of work. There are 1,000 milliwatts in a 1 Watt of work. In 4 hours, there are 14,400 seconds.
Work= Energy/time
17 mW * 1 W/1000 mW = Energy/(14,400 seconds)
Solving for energy,
Energy = 244.8 J
Energy/photon = 244.8 J/(6.04×10²⁰) = 4.053×10⁻¹⁹ J/photon
Using the Planck's equation:
E = hc/λ
where h = 6.626×10⁻³⁴ m²·kg/s, c = 3,00,000,000 m/s and λ is the wavelength
4.053×10⁻¹⁹ J/photon = (6.626×10⁻³⁴ m²·kg/s)(3,00,000,000 m/s)/λ
λ = 4.9×10⁻⁷ m or 49 micrometers