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yKpoI14uk [10]
3 years ago
14

The graph and table shows the relationship between y, the number of words Jean has typed for her essay and x, the number of minu

tes she has been typing on the computer.
According to the line of best fit, about how many words will Jean have typed when she completes 60 minutes of typing?

A.2,500
B.2,750
C.3,000
D.3,250

Mathematics
2 answers:
ryzh [129]3 years ago
7 0
C. 3000 according to the graph 
cupoosta [38]3 years ago
6 0

C. 3,000

hope it helps

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A sample of 100 footballs showed an average air pressure of 13 psi. The standard deviation of the population is known to be .25
Vladimir79 [104]

Answer:

0.025 is the standard error of mean.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 100

Sample mean = 13 psi

Population standard deviation = 0.25 psi

We have to find the standard error of the mean.

Formula:

Standard error =

\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.25}{\sqrt{100}} = \dfrac{0.25}{10} = 0.025

0.025 is the standard error of mean.

7 0
3 years ago
.002 is 1/10 of what
amid [387]
Let the unknown number be x.  Then (1/10)x = 0.002.  To solve for x, multiply both sides by 1000 to remove the decimal fraction 0.002.

Then 1000(1/10)x = 1000(0.002), or 100x = 2.  Dividing both sides by x returns 

x=100/2, or x= 50 (answer)
5 0
3 years ago
Help ASAP show work please thanksss!!!!
Llana [10]

Answer:

\displaystyle log_\frac{1}{2}(64)=-6

Step-by-step explanation:

<u>Properties of Logarithms</u>

We'll recall below the basic properties of logarithms:

log_b(1) = 0

Logarithm of the base:

log_b(b) = 1

Product rule:

log_b(xy) = log_b(x) + log_b(y)

Division rule:

\displaystyle log_b(\frac{x}{y}) = log_b(x) - log_b(y)

Power rule:

log_b(x^n) = n\cdot log_b(x)

Change of base:

\displaystyle log_b(x) = \frac{ log_a(x)}{log_a(b)}

Simplifying logarithms often requires the application of one or more of the above properties.

Simplify

\displaystyle log_\frac{1}{2}(64)

Factoring 64=2^6.

\displaystyle log_\frac{1}{2}(64)=\displaystyle log_\frac{1}{2}(2^6)

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}(2)

Since

\displaystyle 2=(1/2)^{-1}

\displaystyle log_\frac{1}{2}(64)=6\cdot log_\frac{1}{2}((1/2)^{-1})

Applying the power rule:

\displaystyle log_\frac{1}{2}(64)=-6\cdot log_\frac{1}{2}(\frac{1}{2})

Applying the logarithm of the base:

\mathbf{\displaystyle log_\frac{1}{2}(64)=-6}

5 0
2 years ago
What is the function to 5c+4=2 (c-5)
Vinvika [58]
To solve the function we proceed as follows:
5c+4=2(c-5)
opening the parentheses we get:
5c+4=2c-10
putting like terms together we get
5c-2c=-10-4
3c=-14
c=-14/3        
4 0
3 years ago
Charmaine is on the swim team. Each week she swims a total of 6,000 meters. How many kilometers does she swim each week?
alex41 [277]

Answer:

1000m = 1 km

:. 6000m=6000/1000 =6km ans

hope it helps

plz mark as brainliest.

3 0
3 years ago
Read 2 more answers
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