Of heating. Or when the lake is exposed to boil because of the temperature.
Answer: when reactants and products are gases at STP.
Justification:
1) STP stands for standard temperature (0°) and pressure (1 atm).
2) According to the kinetic molecular theory of the gases, and as per Avogadro's principle, equal volumes of gases, at the same temperature and pressure, have the same number of molecules.
3) Since the coefficients in a balanced chemical equation represent number of moles, when reactants and products are gases at the same temperature and pressure, the mole ratios are the same that the volume ratios, and then the coefficients of the chemical equation represent the volume ratios.
Answer:
This is a coal combustion process and we will assume
Inlet coal amount = 100kg
It means that there are
15kg of H2O, 2kg of Sulphur and 83kg of Carbon
Now to find the mole fraction of SO2(g) in the exhaust?
Molar mass of S = 32kg/kmol
Initial moles n of S = 2/32 = 0.0625kmols
Reaction: S + O₂ = SO₂
That is 1 mole of S reacts with 1 mole of O₂ to give 1 mole of SO₂
Then, it means for 0.0625 kmoles of S, we will have 0.0625 kmole of SO2 coming out of the exhaust
The mole fraction of SO2(g) in the exhaust=0.0625kmols
Explanation:
Answer:
H₂(g) +I₂(g) ⟶ 2HI(g)
Explanation:
Kc =Kₚ when the number of moles of gaseous products equals the number of moles of gaseous reactants.
The HI reaction has two moles of gas on each side of the reaction arrow.
K = (Products)ⁿ/(Reactants)ⁿ = (Products/Reactants)ⁿ
Thus, if n is the same for products and reactants, you will get the same number whether you use concentrations or pressures, and Kc = Kₚ
