Answer:
6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.
Explanation:
Using integrated rate law for first order kinetics as:
Where,
is the concentration at time t
is the initial concentration
Given:
Concentration is decreased to 1.56 % which means that 0.0156 of
is decomposed. So,
= 0.0156
Thus,
kt = 4.1604
The expression for the half life is:-
Half life = 15.0 hours
Where, k is rate constant
So,

<u>6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.</u>
Answer:
I believe it's
4-floro-5,6,8-Tribromo-3,3,7-trimethylnonane
Answer:
Explanation:
The question is not complete, the cmplete question is:
Identify one type of noncovalent bond present in each solid.
1) Table salt (NaCl) 2) Graphite (repeating)
a. hydrogen bonds
b. ionic interactions
c. van der Waals interactions
d. hydrophobic interactions
Answer:
1) Table salt
b. ionic interactions
Ionic bond are formed between atoms with incomplete outermost shell. Some atoms add electrons to their outermost shell to make the shell complete hence making it a negative ion while some atoms loses their electron to make the outermost shell complete becoming a positive ion. In NaCl, sodium (Na) has 1 electron in its outermost shell which it transfers to Cl which has 7 electrons in the outermost shell. Hence after the bonding the outermost shell of the atoms become complete.
2) Graphite
c. Van Der Waals interaction
Van der waal forces are weak interaction between molecules that exist between close atoms. Carbon atoms in graphite planes have covalent bond, these graphite planes are known as graphenes. Bonds between graphenes are very weak and are van der waals forces.
Hoi!!
its true
hope this help!!
:) np
<h3>
Answer:</h3>
5.6 L
<h3>
Explanation:</h3>
We are given;
- Initial volume, V1 = 3.5 L
- Initial pressure, P1 = 0.8 atm
- Final pressure, P2 = 0.5 atm
We are required to calculate the final volume;
- According to Boyle's law, the volume of a fixed mass of a gas and the pressure are inversely proportional at a constant temperature.
- That is; P α 1/V
- Mathematically, P=k/V
- At two different pressure and volume;
P1V1 = P2V2
In this case;
Rearranging the formula;
V2 = P1V1 ÷ P2
= (0.8 atm × 3.5 L) ÷ 0.5 atm
= 5.6 L
Therefore, the resulting volume is 5.6 L