2] Calculate the percentage of the element forming sugar glucose C6H1206 [C=12, H=1, 0=16]

Write a chemical equation for the reaction that occurs in the following cell: Cu|Cu2+(aq)||Ag+(aq)|Ag Express your answer as a b

Alinara [238K]

Answer:

Explanation:

The cell reaction properly written is shown below:

Cu|Cu²⁺ $_{aq}$ || Ag⁺ $_{aq}$ | Ag

From this cell reaction, to get the net ionic equation, we have to split the reaction into their proper oxidation and reduction halves. This way, we can know that is happening at the electrodes and derive the overall net equation.

Oxidation half:

Cu $_{s}$ ⇄ Cu²⁺ $_{aq}$ + 2e⁻

At the anode, oxidation occurs.

Reduction half:

Ag⁺ $_{aq}$ + 2e⁻ ⇄ Ag $_{s}$

At the cathode, reduction occurs.

To derive the overall reaction, we must balance the atoms and charges:

Cu $_{s}$ ⇄ Cu²⁺ $_{aq}$ + 2e⁻

Ag⁺ $_{aq}$ + e⁻ ⇄ Ag $_{s}$

we multiply the second reaction by 2 to balance up:

2Ag⁺ $_{aq}$ + 2e⁻ ⇄ 2Ag $_{s}$

The net reaction equation:

Cu $_{s}$ + 2Ag⁺ $_{aq}$ + 2e⁻⇄ Cu²⁺ $_{aq}$ + 2e⁻ + 2Ag $_{s}$

We then cancel out the electrons from both sides since they appear on both the reactant and product side:

Cu $_{s}$ + 2Ag⁺ $_{aq}$ ⇄ Cu²⁺ $_{aq}$ + 2Ag $_{s}$

6 0

3 years ago

40. What is the mass of 3 moles of H 2 O

Leya [2.2K]

Answer:

54g

Explanation:

Given parameters:

Number of moles of H₂O = 3 moles

Unknown:

mass of water = ?

Solution:

To solve this problem, we use the expression below:

mass = number of moles x molar mass

Molar mass of H₂O = 2(1) + 16 = 18g/mol

Mass of water = 3 x 18 = 54g

3 0

3 years ago

Calculate the number of moles in 9.22 X 10^23 atom iron

sveta [45]

1.53 moles of Fe is your solution hope it helps!

7 0

2 years ago

g If 50.0 mL of a 0.75 M acetic acid solution is titrated with 1.0 M sodium hydroxide, what is the pH after 10.0 mL of NaOH have

V125BC [204]

Answer:

pH = 2.66

Explanation:

Acetic Acid + NaOH → Sodium Acetate + H₂O

First we calculate the number of moles of each reactant, using the given volumes and concentrations:

0.75 M Acetic acid * 50.0 mL = 37.5 mmol acetic acid

1.0 M NaOH * 10.0 mL = 10 mmol NaOH

We calculate how many acetic acid moles remain after the reaction:

37.5 mmol - 10 mmol = 27.5 mmol acetic acid

We now calculate the molar concentration of acetic acid after the reaction:

27.5 mmol / (50.0 mL + 10.0 mL) = 0.458 M

Then we calculate [H⁺], using the following formula for weak acid solutions:

[H⁺] = $\sqrt{C*Ka}=\sqrt{0.458M*1.76x10^{-5}}$

[H⁺] = 0.0028

Finally we calculate the pH:

pH = -log[H⁺]

pH = 2.66

8 0

3 years ago

Erythrogenic acid, C18H26O2, is an acetylenic fatty acid that turns avivid red on exposure to light. On catalytic hydrogenation

lara31 [8.8K]

Answer:

use research

Explanation:

6 0

3 years ago

2] Calculate the percentage of the element forming sugar glucose C6H1206[C=12, H=1, 0=16]​

2] Calculate the percentage of the element forming sugar glucose C6H1206[C=12, H=1, 0=16]