The amount of water that must be added to 6.0 M silver nitrate to make 500mL of 1.2 M solution is : 2000 mL
<u>Given data :</u>
Concentration of siilver nitrate ( M₁ ) = 6.0 M
volume of solution ( V₁ ) = 500 mL
Conc of solution ( M₂ )= 1.2 M
<h3>Determine the amount of water that must be added</h3>
we will apply the equation below
M₁V₁ = M₂V₂ ---- ( 1 )
where : V₂ = V₁ + water added ---- ( 2 )
V₂ ( Final volume ) = ( M₁V₁ ) / M₂
= ( 6 * 500 ) / 1.2
= 2500 mL
Back to eqaution ( 2 )
2500 mL = 500 mL + added water
therefore ; added water = 2500 - 500
= 2000 mL
Hence we can conclude that The amount of water that must be added to 6.0 M silver nitrate to make 500mL of 1.2 M solution is : 2000 mL.
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Answer:
200 g
Explanation:
Stainless steel is an alloy of iron, chromium, nickel, and manganese metals. A 2.000 g sample contains 10.0% nickel (mass percent), that is, there are 10.0 g of nickel every 100 g of the sample. The mass of nickel in the sample is:
2.000 g sample × (10.0 g Nickel/100 g sample) = 200 g Nickel
There are 200 grams of Nickel in the 2.000 g-sample.
Answer:
6 neutrons. The mass number is the number of protons and neutrons in the nucleus of an atom. The atomic number shows how many protons. Subract the atomic number from the mass number to find the number of neutrons.
Explanation:
It will be number 1.
NO loses oxygen ie its being reduced to N2
NH3 gains oxygen atom ie its being oxidised to H2O
The overall fusion reaction is the conversion of Hydrogen to Helium
