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3 years ago

Balance the equation: _HgO → _O2 + ___Hg

Chemistry

2 answers:

wel3 years ago

7 0

Answer: $2HgO\rightarrow O_2+2Hg$

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced chemical equation for the reaction is:

$2HgO\rightarrow O_2+2Hg$

Thus if the product is $O_2$ , there are 2 atoms of oxygen. When a coefficient 2 is placed in front of the reactant $HgO$ , there will be 2 atoms of oxygen and 2 atoms of mercury. Thus a coeeficient of 2 is to be added to product side in front of $Hg$ .

olchik [2.2K]3 years ago

3 0

2HgO -> 1 O2 + 2Hg

remember first there's 2 oxygens so then you check the other side and make it 2 too. then you see that now there's 2Hg and then you put a 2 on the other side to make it 2Hg too. balancing is just making sure the number of elements on one side equal the other.

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3 years ago

State which of the following set of quantum number would be possible and which would be permissible for an electron in an atom.

raketka [301]

Answer:

The correct option is: e) n=4, l=3, $m_{l}$ = - 2 , $m_{s}$ = - 1/2

Explanation:

The four quantum numbers that describe the electrons in an atom are: The principal: n, azimuthal: l, magnetic: m, and spin: s.

For a given electron, the values of the quantum numbers should be in the given range- principal quantum number: n ≥ 1;

azimuthal quantum number: 0 ≤ l ≤ n − 1;

magnetic quantum number: −l ≤ $m_{l}$ ≤ +l;

spin quantum number: −s ≤ $m_{s}$ ≤ +s

Now, for n= 4,

The value of l: 0 to n − 1 = 0 to 3 = 0, 1, 2, 3

The value of $m_{l}$ for l= 3 : -3 to +3 = -3, -2, -1, 0, +1, +2, +3

The value of $m_{s}$ : -1/2, +1/2

Therefore, the given set of quantum numbers: n=4, l=3, $m_{l}$ = - 2 , $m_{s}$ = - 1/2; are possible and permissible for an electron in an atom.

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3 years ago

Balance the equation: ___HgO → ___O2 + ___Hg

Balance the equation: _HgO → _O2 + ___Hg