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Jlenok [28]
3 years ago
7

How do you calculate the abundance of an atom and the relative atomic maths? As simply as possible?

Chemistry
1 answer:
chubhunter [2.5K]3 years ago
7 0
By looking it up on the periodic table
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A boy swings a rubber ball attached to a string over his head in a horizontal, circular path. The piece of string is 1.15 m long
gregori [183]

Answer:

v = 16.49 m/s

Explanation:

Given that,

Length of the string, l = 1.15 m

The ball makes 137 complete turns each minute.

We know that, 1 turn = 6.28 rad

137 turns = 860.79 rad

1 min = 60 s

\omega=\dfrac{860.79\ rad}{60\ s}\\\\=14.34\ rad/s

We need to find the tangential velocity of the ball. It can be given by

v=r\omega\\\\=1.15\times 14.34\\\\v=16.49\ m/s

So, the tangential velocity of the ball is 16.49 m/s.

5 0
3 years ago
Polymerization starts at the ________ end of the template.
balandron [24]

Answer:

B.  3'

Explanation:

Polymerization is the process of forming large molecules by joining together many small molecules. The small molecules are known as the monomers, and the macromolecules are called polymers.

There are two(2) types of polymerization.

a. addition polymerization

b. condensation polymerization

Polymerization is characterized by eliminating small molecules such as water, carbon(IV)oxide, methanol e.t.c.

In complex compounds, polymerization starts at the 3' end of the template.

3 0
3 years ago
What affect will adding sugar have on the viscosity of water?
Radda [10]
Sugar increases the viscosity of water

hope that helps
4 0
3 years ago
Read 2 more answers
34. An electron in the 3d state of the hydrogen atom has a radial part of the wave function of the form A r2 exp(-r/3ao). What i
nikdorinn [45]

Answer: Option (e) is the correct answer.

Explanation:

Formula to calculate radius is as follows.

          p(r) = Ar(r^{2}e^{\frac{-r}{3a_{o}}}

                = Ar^{3}e^{\frac{-r}{3a_{o}}}

     \frac{dp(r)}{dr} = 0

            Ar^{3}e^{\frac{-r}{3a_{o}}}(\frac{-1}{3a_{o}} + Ae^{\frac{-r}{3a_{o}}}(3r^{2}) = 0

                     \frac{Ar^{3}}{3a_{o}}e^{\frac{-r}{3a_{o}}}

                      = 3Ar^{2}e^{\frac{-r}{3a_{o}}}

                       r = 9a_{o}

Thus, we can conclude that most likely radius at which the electron would be found is 9a_{o}.

4 0
3 years ago
When the temperature of the gas changes from cold to hot, the amount of pressure is ___________.
klio [65]
<span> Assuming constant volume, if you increase </span>temperature<span>, the </span>pressure<span> will increase. So it is B: increasing</span>
6 0
3 years ago
Read 2 more answers
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