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3 years ago

7

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2 answers:

e-lub [12.9K]3 years ago

7 0

Left wait what are you asking tho
?

butalik [34]3 years ago

7 0

There’s not enough info

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do you think that religion and science are in conflict ,or that people can both have both without any problems

natka813 [3]

Religion and science are fundamentally incompatible. They disagree profoundly on how we obtain knowledge of the world. Science is based observation and reasoning from observation. Religion assumes that human beings can access a deeper level of information that is not available by either observation or reason.

5 0

3 years ago

Read 2 more answers

A scientist has 0.12 miles of a gas at a pressure of 4.06 kPa and a volume of 14 liters in an enclosed container. What is the te

natka813 [3]

Answer:

56972.17K

Explanation:

P = 4.06kPa = 4.06×10³Pa

V = 14L

n = 0.12 moles

R = 8.314J/Mol.K

T = ?

We need ideal gas equation to solve this question

From ideal gas equation,

PV = nRT

P = pressure of the ideal gas

V = volume the gas occupies

n = number of moles

R = ideal gas constant

T = temperature of the gas

PV = nRT

T = PV / nR

T = (4.06×10³ × 14) / (0.12 × 8.314)

T = 56840 / 0.99768

T = 56972.17K

Note : we have a large number for temperature because we converted the value of pressure from kPa to Pa

7 0

3 years ago

What is the molarity of a solution prepared by diluting 43.72 ml of 1.005 M aqueous K2CR2O7 to 500 ml

UNO [17]

Answer:

43.72

Explanation:

that is the answer hope u liked it and I did this already along time ago

3 0

3 years ago

What are The usages of transducer in ultrasonic??

Gennadij [26K]

Answer:they are used to generate sound waves in the ultrasonic range

Explanation:transducers are used to generate sound waves in the ultrasonic range ,by turning electrical energy into sound

8 0

3 years ago

Find an expression for the change in entropy when two blocks of the same substance of equal mass, one at the temperature Th and

Gre4nikov [31]

Explanation:

Relation between entropy change and specific heat is as follows.

$\Delta S = C_{p} log (\frac{T_{2}}{T_{1}})$

The given data is as follows.

mass = 500 g, $C_{p}$ = 24.4 J/mol K

$T_{h}$ = 500 K, $T_{c}$ = 250 K

Mass number of copper = 63.54 g /mol

Number of moles = $\frac{mass}{/text{\molar mass}}$

= $\frac{500}{63.54}$

= 7.86 moles

Now, equating the entropy change for both the substances as follows.

$7.86 \times 24.4 \times [T_{f} - 250]$ = $7.86 \times 24.4 \times [500 -T_{f}]$

$T_{f} - 250 = 500 - T_{f}$

$2T_{f}$ = 750

So, $T_{f}$ = $375^{o}C$

For the metal block A, change in entropy is as follows.

$\Delta S = C_{p} log (\frac{T_{2}}{T_{1}})$

= $24.4 log [\frac{375}{500}]$

= -3.04 J/ K mol

For the block B, change in entropy is as follows.

$\Delta S = C_{p} log (\frac{T_{2}}{T_{1}})$

= $24.4 log [\frac{375}{250}]$

= 4.296 J/Kmol

And, total entropy change will be as follows.

= 4.296 + (-3.04)

= 1.256 J/Kmol

Thus, we can conclude that change in entropy of block A is -3.04 J/ K mol and change in entropy of block B is 4.296 J/Kmol.

8 0

3 years ago