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kogti [31]
4 years ago
15

If the pendulum is taken into the orbiting space station what will happen to the bob? if the pendulum is taken into the orbiting

space station what will happen to the bob? it will continue to oscillate in a vertical plane with the same period. it will no longer oscillate because there is no gravity in space. it will no longer oscillate because both the pendulum and the point to which it is attached are in free fall. it will oscillate much faster with a period that approaches zero.

Physics
1 answer:
mezya [45]4 years ago
3 0
Check the attached file for the answer.

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D. Rutherford found that the atom consists of a small positively charged nucleus.
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Explain the relationship between speed and steepness of the slope of the line on the distance-versus-time graph
balandron [24]

Explanation:

A distance-versus-time graph gives the distance an object has traveled after a given time.

In a distance-versus-time graph the slope represents the the speed of the object because rise/run is

  \frac{\Delta distance }{\Delta time}=speed.

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6 0
3 years ago
What visible wavelengths of light are strongly reflected from a 390-nm-thick soap bubble?
DiKsa [7]

Answer:

So visible wavelength which is possible here is

416 nm and 693.3 nm

Explanation:

As we know that for normal incidence of light the path difference of the reflected ray is given as

2\mu t + \frac{\lambda}{2} = \Delta x

so here we can say that for maximum intensity condition we will have

\Delta x = N\lambda

so we have

2\mu t + \frac{\lambda}{2} = N\lambda

now for visible wavelength we have

for N = 1

2\mu t = \frac{\lambda}{2}

\lambda = 4\mu t

\lambda = 4(\frac{4}{3})(390 nm)

\lambda = 2080 nm

for N = 2

\lambda = \frac{4\mu t}{3}

\lambda = \frac{4(\frac{4}{3})(390 nm)}{3}

\lambda = 693.3 nm

for N = 3

\lambda = \frac{4\mu t}{5}

\lambda = \frac{4(\frac{4}{3})(390 nm)}{5}

\lambda = 416 nm

6 0
4 years ago
Select the correct answer.
lutik1710 [3]
I’m sorry i haven’t found the answer to this
8 0
3 years ago
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