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Thepotemich [5.8K]
2 years ago
6

An unknown amount of a radioactive isotope with a half-life of 2.0 h was observed for 6.0 h. if the amount of the isotope remain

ing after 6.0 h was 24 g, what would the original amount have been?
Physics
1 answer:
Grace [21]2 years ago
5 0

The original amount of the radioactive isotope will be 8 grams.

<h3 /><h3>What is the half-life of radioisotopes?</h3>

The amount of time required for half of a radioisotope's nuclide to decay, or change into a different species, is known as its half-life. The conversions release either beta or alpha particles, and the response can be monitored by counting the particles released.

Given that an unknown amount of a radioactive isotope with a half-life of 2.0 h was observed for 6.0 h. if the amount of the isotope remaining after 6.0 h was 24 g.

The original amount will be calculated as below:-

( 2 / 6 ) = ( Original amount / 24 )

Original amount = 4 x 2

Original amount = 8 grams

Therefore, the original amount of the radioactive isotope will be 8 grams.

To know more about the half-life of radioisotopes follow

brainly.com/question/1783783

#SPJ4

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A record turntable is rotating at 33 rev/min. A watermelon seed is on the turntable 4.0 cm from the axis of rotation. (a) Calcul
Annette [7]

Answer:

a) a = 0.477 m/s^2

b) u = 0.04862

Explanation:

Given:-

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Find:-

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                   w = 2π*33 / 60

                   w = 3.456 rad/s

- The watermelon seed undergoes a centripetal acceleration ( α ) defined by:

                   α = w^2 * r

                   α = 3.456^2 * 0.04

                   α = 0.477 m / s^2

- The minimum friction force (Ff) is proportional to the contact force of the seed.

- The weight (W) of the seed with mass m acts downwards. The contact force (N) can be determined from static condition of seed in vertical direction.

                   N - W = 0

                   N = W = m*g

- The friction force of the (Ff) is directed towards the center of axis of rotation, while the centripetal force acts in opposite direction. The frictional force Ff = u*N = u*m*g must be enough to match the centripetal force exerted by the turntable on the seed.

                    Ff = m*a

                    u*m*g = m*a

                    u = a / g

                    u = 0.477 / 9.81

                    u = 0.04862

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