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Virty [35]
3 years ago
12

On a piece of paper, graph this system of inequalities. Then determine which region contains the solution to the system.

Mathematics
2 answers:
Mashutka [201]3 years ago
3 0

we have

y\leq \frac{1}{4}x+3 ----> inequality 1

The solution of the inequality 1 is the shaded area below the solid red line

The solution is the region D and region C

y\geq-x+5 -----> inequality 2

The solution of the inequality 2 is the shaded area above the solid blue line

The solution is the region B and region C

The solution of the system is the common area

so

The solution is the region C

see the attached figure

therefore

the answer is the option C

Region C

konstantin123 [22]3 years ago
3 0

Answer:

Region C of  the graph will contains the solution to the given system

Step-by-step explanation:

 Consider the given system of equation

y\le\frac{1}{4}x+3

and y\ge-x+5

We have to choose the region of the graph that contains the solution to the given system.

Since, to determine the region choose  a test point in each region and then then check the values of inequality at that point and for the test point that satisfies both the inequality  will contains the solution to the given system.

On region A)

Let (0, 4)  be the test point that lies in region A

Then put the value of x = 0 and y= 4 in given system,

we have,

4\le\frac{1}{4}(0)+3 \Rightarrow 4\le 3 (false)

and 4\ge(0)+5 \Rightarrow 4\ge 5 (false)

On region B)

Let (0, 8)  be the test point that lies in region B

Then put the value of x = 0 and y= 8 in given system,

we have,

8\le\frac{1}{4}(0)+3 \Rightarrow 8\le 3 (false)

and 8\ge(0)+5 \Rightarrow 8\ge 5 (true)

On region C)

Let (8,0)  be the test point that lies in region C

Then put the value of x = 8 and y= 0 in given system,

we have,

0\le\frac{1}{4}(8)+3 \Rightarrow 0\le 5 (true)

and 0\ge(-8)+5 \Rightarrow 0\ge -3 (true)

On region D)

Let (0,0)  be the test point that lies in region D

Then put the value of x = 0 and y= 0 in given system,

we have,

0\le\frac{1}{4}(0)+3 \Rightarrow 0\le 3 (false)

and 0\ge(0)+5 \Rightarrow 0\ge 5 (false)

Thus, only (8,0)  be the test point that lies in region C satisfies both inequality.

Thus, region C of  the graph will contains the solution to the given system

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Answer:

(275,122)  

When the price will be $275, the quantity will be 122 televisions.

Step-by-step explanation:

We have been given that a group of retailers will buy 104 televisions from a wholesaler if the price is $300 and 144 if the price is $250.

As the quantity of televisions depends on price of televisions, so our demand curve will pass through points (300,104) and (250,144).

Let us find slope of demand line using slope formula.

m=\frac{y_2-y_1}{x_2-x_1}, where,

m =\text{Slope of line},

y_2-y_1=\text{Difference between two y-coordinates},

x_2-x_1=\text{Difference between same x-coordinates of two y-coordinates}

Upon substituting coordinates of our given points in slope formula we will get,

m=\frac{104-144}{300-250}

m=\frac{-40}{50}

m=-\frac{4}{5}

Let us substitute m=-\frac{4}{5} coordinates of point (250,144) in slope intercept form of equation (y=mx+b).

144=-\frac{4}{5}*250+b

144=-4*50+b

144=-200+b

144+200=-200+200+b

344=b

Upon substituting b=344 and m=-\frac{4}{5} we will get equation of our demand line as:

y=-\frac{4}{5}x+344

Similarly we will find the equation of supply line using points (225,88) and (315,168).  

m=\frac{168-88}{315-225}

m=\frac{80}{90}

m=\frac{8}{9}

Let us substitute m=\frac{8}{9} and coordinates of point (225,88) in slope intercept form of equation (y=mx+b).

88=\frac{8}{9}*225+b

88=8*25+b

88=200+b

88-200=200-200+b

-112=b

Upon substituting b=-112 and m=\frac{8}{9} we will get equation of our supply line as:

y=\frac{8}{9}x-122

Let us equate both lines to find the point where both lines intersect.

-\frac{4}{5}x+344=\frac{8}{9}x-122

-\frac{4}{5}x-\frac{8}{9}x+344=\frac{8}{9}x-\frac{8}{9}x-122

-\frac{4}{5}x-\frac{8}{9}x+344=-122

-\frac{4}{5}x-\frac{8}{9}x+344-344=-122-344

-\frac{4}{5}x-\frac{8}{9}x=-466

Let us have a common denominator.

-\frac{4*9}{5*9}x-\frac{8*5}{9*5}x=-466

-\frac{36}{45}x-\frac{40}{45}x=-466

\frac{-36-40}{45}x=-466

\frac{-76}{45}x=-466

\frac{-76}{45}*\frac{45}{-76}x=-466*\frac{45}{-76}

x=466*\frac{45}{76}

x=6.1315789473684211*45

x=275.9210526315789495\approx 275

Let us substitute x=275 in any of our equation to solve for y.

y=-\frac{4}{5}*275+344

y=-4*55+344

y=-220+344

y=122

Therefore, the equilibrium point for the market will be (275,122).

5 0
3 years ago
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