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Aneli [31]
3 years ago
11

2.50 Consider the following message: FORMULA FOR SUCCESS (a) Estimate the probabilities of the letters in the message using the

relative frequency approach. (b) Find the average information in the message.
Engineering
1 answer:
snow_lady [41]3 years ago
7 0

Answer:

Part a: The probability of each letter is given in the table below.

Part b: The average information in this message is 1.91.

Explanation:

Part a:

The message is given as

FORMULA FOR SUCCESS

Total number is given as n=17

Letter            x                Probability p(x)

F                    2                   2/17

O                   2                   2/17

R                    2                   2/17

M                   1                    1/17

U                   2                   2/17

L                    1                    1/17

A                   1                    1/17

S                   3                   3/17

C                   2                    2/17

E                   1                    1/17

Part b

The information is given as \sum{xp(x)}

Letter            x                Probability p(x)          xp(x)

F                    2                   2/17                         4/17

O                   2                   2/17                         4/17

R                    2                   2/17                         4/17

M                   1                    1/17                          1/17

U                   2                   2/17                         4/17

L                    1                    1/17                          1/17

A                   1                    1/17                          1/17

S                   3                   3/17                         9/17

C                   2                   2/17                        4/17

E                   1                    1/17                          1/17

______________________________________

Total                                                                1.91

So the average information in this message is 1.91.

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Answer:

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Explanation:

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