A force of 16,000 will cause a 1 1 bar of magnesium to stretch from 10 to 10.036 . Calculate the modulus of elasticity in . (Ent
1 answer:
The modulus of elasticity is 44.4GPa
E<u>xplanation:</u>
Given
original length L1=10cm
New length L2=10.036 cm
Force F=16000N
Stress of the bar σ=Force/Area
Change in length ΔL=L2-L1=10.036-10=0.036 cm
Strain is obtained by dividing the change in length by original length
Strain ε=ΔL/L1
=0.036/10=0.0036
Modulus of elasticity=stress/strain
=σ/ε
Pa
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Answer:
Step 1 of 3
Case A:
AISI 1018 CD steel,
Fillet radius at wall=0.1 in,
Diameter of bar
From table deterministic ASTM minimum tensile and yield strengths for some hot rolled and cold drawn steels for 1018 CD steel
Tensile strength
Yield strength
The cross section at A experiences maximum bending moment at wall and constant torsion throughout the length. Due to reasonably high length to diameter ratio transverse shear will be very small compared to bending and torsion.
At the critical stress elements on the top and bottom surfaces transverse shear is zero
Explanation:
See the next steps in the attached image
