The rate of heat transfer by the air conditioner using constant specific heat of 1.004kj/kg.K is 15.06 kW.
<h3>What is the rate of heat transfer?</h3>Rate of heat transfer is the power rating of the machine.
Work done and changes in potential and kinetic energy are neglected since it is a steady state process.
The specific heat in terms of specific heat capacity and temperature change is given as:
The rate of heat transfer, is then determined as follows:
Qout = 0.75 × 20.08 = 15.06 kW
Therefore, the rate of heat transfer by the air conditioner is 15.06 kW.
Learn more about rate of heat transfer at: brainly.com/question/17152804
#SPJ1
Answer
Assuming
At 10000 m height temperature T = -55 C = 218 K
At 1000 m height temperature T = 0 C = 273 K
R = 287 J/kg K
V₂ = V₁ ×1.1222
V₁ = 0.5 × C₁ = 0.5 × 295 = 147.5 m/s
V₂ = 1.1222 × 147.5 = 165.49 m/s
so, the jetliner need to increase speed by ( V₂ -V₁ )
= 165.49 - 147.5
= 17.5 m/s
Answer:
solution in the picture attached
Explanation:
