The air conditioner in a house or a car has a cooler that brings atmospheric air from 30C to 10C, with both states at 101KPa. If
1 answer:
The rate of heat transfer by the air conditioner using constant specific heat of 1.004kj/kg.K is 15.06 kW.
<h3>What is the rate of heat transfer?</h3>Rate of heat transfer is the power rating of the machine.
Work done and changes in potential and kinetic energy are neglected since it is a steady state process.
The specific heat in terms of specific heat capacity and temperature change is given as:
The rate of heat transfer, is then determined as follows:
- Qout = flow rate × specific heat
Qout = 0.75 × 20.08 = 15.06 kW
Therefore, the rate of heat transfer by the air conditioner is 15.06 kW.
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Answer:
Test code:
>>u=10;
>>g=9.8;
>>q=100;
>>m0=100;
>>vstar=10;
>>tstar=fzero_rocket_example(u, g, q, m0, vstar)
Explanation:
See attached image
Explanation:
The obtained data from water properties tables are:
Point 1 (condenser exit) @ 8 KPa, saturated fluid
Point 2 (Pump exit) @ 18 MPa, saturated fluid & @ 4 MPa, saturated fluid
Point 3 (Boiler exit) @ 18 MPa, saturated steam & @ 4 MPa, saturated steam
Point 4 (Turbine exit) @ 8 KPa, mixed fluid
Calculate mass flow rates
Part a) @ 18 MPa
mass flow
Heat transfer rate through boiler
Heat transfer rate through condenser
Thermal Efficiency
Part b) @ 4 MPa
mass flow
Heat transfer rate through boiler
Heat transfer rate through condenser
Thermal Efficiency