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3 years ago

Refrigerant-134a is to be cooled by water in a condenser. The refrigerant enters

Engineering

1 answer:

KonstantinChe [14]3 years ago

4 0

Answer:

Refrigerant R-134a is to be cooled by waterin a condenser.The refrigerant enters thecondenser with a mass flow rate of 6 kg/minat 1 MPa and 70 C and exits at 35 C. The cool-ing water enters at 300 kPa and 15 C andleaves at 25 C. Neglecting pressure drops,determine a) the required mass flow rate ofthe cooling water, and b) the heat transferrate from the refrigerant to the water.SolutionFirst consider the condenser as the control volume. The process is steady,adiabatic and no work is done. Thus over any time intervalΔt,ΔEΔt=0and thusXin˙E=Xout˙Ewhere˙E=˙m h+12V2+gz650:351 Thermodynamics·Prof. Doyle Knight37

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3 years ago

Shear plane angle and shear strain: In an orthogonal cutting operation, the tool has a rake angle = 16°. The chip thickness befo

Oduvanchick [21]

Answer:

shear plane angle Ф = 26.28°

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Explanation:

given data

angle = 16°

chip thickness t1 = 0.32 mm

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solution

we get here first chip thickness ratio that is

chip thickness ratio = $\frac{t1}{t2}$ ................. 1

put here value

chip thickness ratio = $\frac{0.32}{0.72}$

chip thickness ratio r = 0.45

so here shear angle will be Ф

tan Ф = $\frac{r*cos\alpha }{1-rsin\alpha}$ ............2

tan Ф = $\frac{0.45*cos16 }{1-rsin16}$

tan Ф = 0.4938

Ф = 26.28°

and

now we get shear strain that is

shear strain r = cot Ф + tan (Ф - α ) ................3

shear strain r = cot(26.28) + tan (26.28 - 16 )

shear strain r = 2.20

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3 years ago

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