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PtichkaEL [24]
3 years ago
15

A man that is 6 feet tall casts a shadow 5 feet long. At the same time, a lamppost beside the man casts a shadow 25 feet long. H

ow tall is the lamppost?
Mathematics
1 answer:
Montano1993 [528]3 years ago
5 0

Answer:

The answer to your question is:  L = 30 ft

Step-by-step explanation:

Data

man = 6 ft

man shadow = 5 ft

lamppost shadow = 25 ft

lamppost height = ? = L

Process

                   \frac{6}{5} = \frac{L}{25}

                    L = \frac{6 x 25}{5}

                    L = \frac{150}{5}

                           L = 30 ft

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Check the picture below.

\bf \textit{using the pythagorean theorem}
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c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
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a=adjacent\\
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\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\
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\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~  cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~  tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}
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3 0
3 years ago
Using this table below, what is the rate of change? Don't forget to include your units.
NeX [460]
(24,18)(28,21)
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3 0
3 years ago
TIVITY MODULE
bezimeni [28]

Answer: Length: 4, width: 6

Step-by-step explanation:

Let the length be x and width be y

Then x=2y-8 and xy=24

Substitute to get 2y-8 * y = 24, so 2y^2-8y=24 or y^2-4y=12, then solve to get y=6 or y=-2. Since width is positive y=6.

Substitute y=6 into xy=24 to get x=4.

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Hope that helped,

-sirswagger21

6 0
3 years ago
Make a the subject of a2+b2=c2
wel

Answer:

a=\sqrt{c^2-b^2

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Step-by-step explanation:

Given expression:

a^2+b^2=c^2

We need to make a the subject.

In order to do that we need to solve the expression for a in terms of b and c

We have,

a^2+b^2=c^2

Subtracting both sides by b^2

a^2+b^2-b^2=c^2-b^2

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The difference of squares can be factorized and written  as:

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3 years ago
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Decimal points form :brainly.com/question/232702

Keywords : hundred, ten thousandths,decimal

#LearnwithBrainly

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