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4 years ago

What is causing the plates of granite rock to flake off

Physics

2 answers:

butalik [34]4 years ago

6 0

Earth erosion maybe

Taya2010 [7]4 years ago

4 0

A change in pressure once exposed at the surface. -Apex

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A pitot tube system measures the static pressure in 50 cm diameter duct containing air (\rho\:=rho =1.1 kg/m3) as 97 kPa and the

erastova [34]

Answer:

The velocity in duct is 73.854 m/s.

Explanation:

Given that Pitot tube measuring velocity v in 50 cm diameter duct contain air of density 1.1 $\frac{kg}{m^{3} }$ .

Also, P1 = Pressure in duct is 97kpa and P2 = Pressure at impact or stagnation point is 100kpa.

Using Bernoulli equation,

$P+\frac{1}{2}\rho v^{2} +\rho gh=0$

When air is flowing through duct,

$97,000+\frac{1}{2}\rho v^{2} +\rho gh1=0$

When air is at stagnation point.

$1,00,000+0+\rho gh1=0$

Comparing both the equation,

$97,000+\frac{1}{2}\rho v^{2} +\rho gh1=1,00,000+\rho gh1$

$\frac{1}{2}\rho v^{2}=3000$

$0.55v^{2}=3000$

$v^{2}=5454.54$

v=73.854 m/s.

Therefore, The velocity in duct is 73.854 m/s.

4 0

3 years ago

If you are trying to loosen a stubborn screw from a piece of wood with a screwdriver and fail, should you find a screwdriver for

dmitriy555 [2]

A fatter handle. This allows you to provide more torque to the screw, which should eventually loosen it.

4 0

3 years ago

Read 2 more answers

A bee beats its wings approximately 184 times per second. what is its wave period?

sergejj [24]

Answer: It's 0.00543

4 0

3 years ago

Read 2 more answers

A proton initially at rest is accelerated by a uniform electric field. The proton moves 4.76 cm in 1.10 x 10^-6 s. Find the volt

iVinArrow [24]

Answer:

The voltage drop through which the proton moves is 39.1 V.

Explanation:

Given that,

Distance = 4.76 cm

Time $t=1.10\times10^{-6}\ s$

We need to calculate the acceleration

Using equation of motion

$s = ut+\dfrac{1}{2}at^2$

Where, s = distance

a = acceleration

t = time

Put the value in the equation

$4.76\times10^{-2}=\dfrac{1}{2}\times a \times(1.10\times10^{-6})^2$

$a=\dfrac{2\times 4.76\times10^{-2}}{(1.10\times10^{-6})^2}$

$a=7.87\times10^{10}\ m/s^2$

We need to calculate the voltage drop

Using formula of electric field

$F=qE$

$F = q\dfrac{V}{d}$ ....(I)

Using newton's second law

$F = ma$ ....(II)

Put the value of F in equation (I) from equation (II)

$ma=\dfrac{qV}{d}$

$V=\dfrac{mad}{q}$

Where, q = charge

a = acceleration

d = distance

m= mass of proton

Put the value into the formula

$V=\dfrac{1.67\times10^{-27}\times7.87\times10^{10}\times4.76\times10^{-2}}{1.6\times10^{-19}}$

$V=39.1\ V$

Hence, The voltage drop through which the proton moves is 39.1 V.

8 0

3 years ago

Movement of a stationary object

castortr0y [4]

That is a paradox b/c stationary means not moving

5 0

3 years ago