Question

Cierto volumen de gas se encuentra a 60°c de temperatura y 5atm de presión, es calentado hasta 140°c, estado en el cual ocupa un volumen de 680 litros a 7atm. Hallo el volumen del gas

Answer 1

Answer:

V1 = 2221.33 L

Explanation:

The system is about a ideal gas. Then you can use the equation for ideal gases for a volume V1, temperature T1 and pressure P1:

$P_1V_1=nRT_1$   (1)

And also for the situation in which the variables T, V and P has changed:

$P_2V_2=nRT_2$   (1)

R: constant of ideal gases = 0.082 L.atm/mol.K

For both cases (1) and (2) the number of moles are the same. Next, you solve for n in (1) and (2):

$n=\frac{P_1V_1}{RT_1}\\\\n=\frac{P_2V_2}{RT_2}$

Next, you equal these equations an solve for T2:

$\frac{P_1V_1}{RT_1}=\frac{P_2V_2}{RT_2}\\\\V_1=\frac{P_2V_2T_1}{P_1T_2}$

Finally you replace the values of P2, V2, T1 and T2:

$V_1=\frac{(7atm)(680L)(140\°C)}{(60\°C)(5atm)}=2221.33\ L$

Hence, the initial volume of the gas is 2221.33 L