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Komok [63]
3 years ago
15

Line segment XY is tangent to circle Z at point U. If the measure of is 84°, what is the measure of ? 42° 84° 96° 168°

Mathematics
2 answers:
Andreas93 [3]3 years ago
7 0

Answer:

The measure of angle YUV is equal to m

Step-by-step explanation:

see the attached figure to better understand the problem

we have that

arc\ UV=84\° -----> given problem

so

m ------> by central angle

we know that

The triangle UZV is an isosceles triangle

because

ZU=ZV=radius

so

m -----> bases angle of the isosceles triangle

Remember that

The sum of the internal angles of a triangle is equal to 180\°

so

m

2m

substitute and solve for m<ZUV

2m

m

m ------> by complementary angles

solve for m<YUZ

48\°+m

m

marin [14]3 years ago
4 0

Answer:

a 42

Step-by-step explanation:

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Can somebody plz help answer all these questions correctly!! (Only if u know or remember how to do this) lol thanks!!!
kvasek [131]

Answer:

17. 42

18. 12

19. 12

20. 12

Step-by-step explanation:

Simply substitute the given values into the variables. So if m = 6 and n = 2:

7m = 7(6) = 42

6n = 6(2) = 12

mn = (6)(2) = 12

3m - 6 = 3(6) - 6 = 18 - 6 = 12

6 0
3 years ago
Read 2 more answers
Which of the following relation is a function? A.{(0,2),(3,6),(0,1),(6,3)}B. {(1,2),(6,7),(9,9),(3,7)} C.{(4,5),(1,3),(5,5),(4,0
valkas [14]
Heya user☺☺

Option c is correct

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6 0
3 years ago
A box with a square base and open top must have a volume of 296352 c m 3 . We wish to find the dimensions of the box that minimi
mestny [16]

Answer:

  • Base Length of 84cm
  • Height of 42 cm.

Step-by-step explanation:

Given a box with a square base and an open top which must have a volume of 296352 cubic centimetre. We want to minimize the amount of material used.

Step 1:

Let the side length of the base =x

Let the height of the box =h

Since the box has a square base

Volume, V=x^2h=296352

h=\dfrac{296352}{x^2}

Surface Area of the box = Base Area + Area of 4 sides

A(x,h)=x^2+4xh\\$Substitute h=\dfrac{296352}{x^2}\\A(x)=x^2+4x\left(\dfrac{296352}{x^2}\right)\\A(x)=\dfrac{x^3+1185408}{x}

Step 2: Find the derivative of A(x)

If\:A(x)=\dfrac{x^3+1185408}{x}\\A'(x)=\dfrac{2x^3-1185408}{x^2}

Step 3: Set A'(x)=0 and solve for x

A'(x)=\dfrac{2x^3-1185408}{x^2}=0\\2x^3-1185408=0\\2x^3=1185408\\$Divide both sides by 2\\x^3=592704\\$Take the cube root of both sides\\x=\sqrt[3]{592704}\\x=84

Step 4: Verify that x=84 is a minimum value

We use the second derivative test

A''(x)=\dfrac{2x^3+2370816}{x^3}\\$When x=84$\\A''(x)=6

Since the second derivative is positive at x=84, then it is a minimum point.

Recall:

h=\dfrac{296352}{x^2}=\dfrac{296352}{84^2}=42

Therefore, the dimensions that minimizes the box surface area are:

  • Base Length of 84cm
  • Height of 42 cm.
5 0
3 years ago
What is one plus one​
Ronch [10]

Answer:

2

Step-by-step explanation:

1+1=2

5 0
3 years ago
Read 2 more answers
X^2-18x+67=0 Solve the quadratic equation by completing the square.
Assoli18 [71]

Answer:

x = 9 ± √14

Step-by-step explanation:

x² − 18x + 67 = 0

Move the constant to the other side:

x² − 18x = -67

Take half of -18, square it, and add to both sides.

(-18/2)² = (-9)² = 81

x² − 18x + 81 = -67 + 81

x² − 18x + 81 = 14

Factor the perfect square:

(x − 9)² = 14

Solve for x:

x − 9 = ±√14

x = 9 ± √14

5 0
3 years ago
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