Answer:
17. 42
18. 12
19. 12
20. 12
Step-by-step explanation:
Simply substitute the given values into the variables. So if m = 6 and n = 2:
7m = 7(6) = 42
6n = 6(2) = 12
mn = (6)(2) = 12
3m - 6 = 3(6) - 6 = 18 - 6 = 12
Which of the following relation is a function? A.{(0,2),(3,6),(0,1),(6,3)}B. {(1,2),(6,7),(9,9),(3,7)} C.{(4,5),(1,3),(5,5),(4,0
valkas [14]
Heya user☺☺
Option c is correct
Hope this will help☺☺
Answer:
- Base Length of 84cm
- Height of 42 cm.
Step-by-step explanation:
Given a box with a square base and an open top which must have a volume of 296352 cubic centimetre. We want to minimize the amount of material used.
Step 1:
Let the side length of the base =x
Let the height of the box =h
Since the box has a square base
Volume, 

Surface Area of the box = Base Area + Area of 4 sides

Step 2: Find the derivative of A(x)

Step 3: Set A'(x)=0 and solve for x
![A'(x)=\dfrac{2x^3-1185408}{x^2}=0\\2x^3-1185408=0\\2x^3=1185408\\$Divide both sides by 2\\x^3=592704\\$Take the cube root of both sides\\x=\sqrt[3]{592704}\\x=84](https://tex.z-dn.net/?f=A%27%28x%29%3D%5Cdfrac%7B2x%5E3-1185408%7D%7Bx%5E2%7D%3D0%5C%5C2x%5E3-1185408%3D0%5C%5C2x%5E3%3D1185408%5C%5C%24Divide%20both%20sides%20by%202%5C%5Cx%5E3%3D592704%5C%5C%24Take%20the%20cube%20root%20of%20both%20sides%5C%5Cx%3D%5Csqrt%5B3%5D%7B592704%7D%5C%5Cx%3D84)
Step 4: Verify that x=84 is a minimum value
We use the second derivative test

Since the second derivative is positive at x=84, then it is a minimum point.
Recall:

Therefore, the dimensions that minimizes the box surface area are:
- Base Length of 84cm
- Height of 42 cm.
Answer:
2
Step-by-step explanation:
1+1=2
Answer:
x = 9 ± √14
Step-by-step explanation:
x² − 18x + 67 = 0
Move the constant to the other side:
x² − 18x = -67
Take half of -18, square it, and add to both sides.
(-18/2)² = (-9)² = 81
x² − 18x + 81 = -67 + 81
x² − 18x + 81 = 14
Factor the perfect square:
(x − 9)² = 14
Solve for x:
x − 9 = ±√14
x = 9 ± √14