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Romashka [77]
3 years ago
5

The level of a lake was 8 inches below normal. It decreased 1 1/4 inches in June and 2 3/8 inches more in July. What was the new

level with respect to the normal level?
Mathematics
2 answers:
marshall27 [118]3 years ago
8 0

It would be: 8 - (1 1/4 + 2 3/8)

8 - (5/4 + 19/8)

8-29/8

64-29/8

35/8 inches OR  4.375 is your answer

maria [59]3 years ago
8 0
I think you answers is 2.875 
if wrong . im sorry about that
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boyakko [2]

Answer:

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Step-by-step explanation:

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8 0
2 years ago
How many times longer is 3 1/2 to 2 1/2
Alik [6]

Answer:

1.4 times as long

Step-by-step explanation:

3 1/2 (convert to mixed number) --> 7/2

2 1/2 (convert to mixed number) --> 5/2

(7/2) / (5/2) --> 7/5 --> 1.4

3 0
2 years ago
Read 2 more answers
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aalyn [17]
The equation is 30,000+200x=80,000. X is the number of sales.
8 0
3 years ago
In 2002, there were 972 students enrolled at Oakview High School. Since then, the number of students has increased by 1.5% each
Rudiy27

Answer:

N(t) = 972(1.015)^{t}

Growth function.

The number of students enrolled in 2014 is 1162.

Step-by-step explanation:

The number of students in the school in t years after 2002 can be modeled by the following function:

N(t) = N(0)(1+r)^{t}

In which N(0) is the number of students in 2002 and r is the rate of change.

If 1+r>1, the function is a growth function.

If 1-r<1, the function is a decay function.

In 2002, there were 972 students enrolled at Oakview High School.

This means that N(0) = 972

Since then, the number of students has increased by 1.5% each year.

Increase, so r is positive. This means that r = 0.015

Then

N(t) = N(0)(1+r)^{t}

N(t) = 972(1+0.015)^{t}

N(t) = 972(1.015)^{t}

Growth function.

Find the number of students enrolled in 2014.

2014 is 2014-2002 = 12 years after 2002, so this is N(12).

N(t) = 972(1.015)^{t}

N(12) = 972(1.015)^{12}

N(12) = 1162

The number of students enrolled in 2014 is 1162.

7 0
3 years ago
ANSWER FASTTTT!!!
Veseljchak [2.6K]

Answer:

14

Step-by-step explanation:

6 0
3 years ago
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